Parse a line in Java

Question

String line = "a:b:c:d"   // Valid

In the above line , I have 4 values separated by 3 ":".

Sting invalidLine = "a:b:c" //Invalid

As 4th value is missing

String invalidLine = "a:b:c:"  //Invalid

As 4th value is missing .

I want to spit it the line on count ofdelimiter ":".

http://www.google.lk/search?q=split+string+in+java&aq=0&oq=split+string+&sourceid=chrome&ie=UTF-8 — ironwood, Feb 21 '13 at 12:24
split the string with ":" to an array and find the length of array. — Rais Alam, Feb 21 '13 at 12:27

Malcolm Murray · Accepted Answer · 2013-02-21T12:49:50.033

Nice and easy, just use:

String[] stringValidTokens = line.split(":");

Gives you a String array which you can compare to the invalid string array, either by iterating or by checking number of items to check if valid or not.... or do whatever you like with it.

So to compare both strings do something like:

boolean valid = false;
String[] stringValidTokens = line.split(":");
String[] stringinValidTokens = invalidline.split(":");
if(stringValidTokens.size() == stringInvalidTokens.size()){
valid = true;
}

score 0 · Answer 2 · edited Jun 20 '20 at 09:12

I want to spit it the line on count ofdelimiter ":".

This code is splitting the given string on count of ofdelimiter ":"

public static void main(String[] args) {
    String line = "a:b:c:d";
    int count = line.length() - line.replace(":", "").length();
    System.out.println(count);
    String[] str = null;
    if (count == 3) {
        str = line.split(":");
        System.out.println(Arrays.toString(str));
        if (Arrays.asList(str).contains("") || str.length < 4)
            System.out.println("Invalid");
    } else {
        
        System.out.println("Invalid");
    }

}

Parse a line in Java

2 Answers2