How to create small dict from another dict with array of keys?

Question

I have a simple dictionary {'a': 1, 'b': 2, 'c': 3, 'd': 4 } and list of keys: ['a', 'd'].

What is the better way to construct dict object containing only keys from the list: {'a': 1, 'd': 4}?

This was already answered here: http://stackoverflow.com/questions/11157704/python-intersection-between-a-list-and-keys-of-a-dictionary — Udo Klein, Feb 27 '13 at 10:20
I'm new to python, simple "for" loop, but it looks awful: d={'a': 1, 'b': 2, 'c': 3, 'd': 4 } l=['a','d'] r={} for key in l: r[key]=d[key] — user2114842, Feb 27 '13 at 10:22

eumiro · Accepted Answer · 2013-02-27T10:24:07.537

2

d = {'a': 1, 'b': 2, 'c': 3, 'd': 4 }
l = ['a', 'd']

new_d = {k:d[k] for k in l}

new_d is now {'a': 1, 'd': 4}

edited Feb 27 '13 at 10:24

answered Feb 27 '13 at 10:18

eumiro

nice answer, [here is a method](http://stackoverflow.com/questions/1747817/python-create-a-dictionary-with-list-comprehension?answertab=votes#tab-top) using `dict()` how to use for this purpose. – Grijesh Chauhan Feb 27 '13 at 10:32

score 0 · Answer 2 · answered Feb 27 '13 at 14:17

0

d = {'a':1, 'b':2, 'c':3, 'd':4}
c = ['a', 'b']
new_d = {}

for key in c:
    new_d[key]= d[key]

answered Feb 27 '13 at 14:17

2 Answers2