Wrong value coming from the jsonobject - java

Question

This is the continuation of my last question: how to keep data stored into a hashtable - java

Here is the json:

{"DeviceID":"35181805087546548","TotalCount":"0","Timestamp":"2013-03-05 14:30:15"}

Here is the declaration of my hashtable:

    private static Hashtable<Integer,String> table = new Hashtable<Integer,String>();
    private static AtomicInteger count = new AtomicInteger() ;

Here is code to parse the jsonobject:

        JSONObject jsonObj;
        try {
            jsonObj = new JSONObject(string);
            int id = jsonObj.optInt("DeviceID", count.addAndGet(1) );
            String name = jsonObj.toString();
            table.put(id, name);
        } catch (JSONException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }

Using the code below my id is always "2147483647" even if the "DeviceID" in the json changes. Any hint?

Many thanks

score 4 · Accepted Answer · edited May 23 '17 at 12:21

4

Your value is too large for an int. The largest allowable value is 2,147,483,647. See What is the maximum value for an int32?. You will need to parse the value as a long.

edited May 23 '17 at 12:21

Community

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answered Mar 05 '13 at 20:42

Mike Hogan

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Sotirios, made the answer a statement rather that a question – Mike Hogan Mar 05 '13 at 20:46
+1 Looked like a valid answer before, so does it now. No need to be rude. – Fritz Mar 05 '13 at 20:46

score 1 · Answer 2 · answered Mar 05 '13 at 20:43

1

The maximum value of an integer in Java is 2,147,483,647, so your device ID doesn't fit. You will probably need to store it as a long (maximum value 9,223,372,036,854,775,807).

answered Mar 05 '13 at 20:43

Brendan Long

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score 1 · Answer 3 · answered Mar 05 '13 at 20:43

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The number you are getting is the maximum value of a signed integer, you need to use long, or your result is limited to Integer.MAX_VALUE.

answered Mar 05 '13 at 20:43

Chris Cooper

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Wrong value coming from the jsonobject - java

3 Answers3