Why doesn't the regex (?<=fo).* match foo (whereas (?<=f).* does)?
"foo" =~ /(?<=f).*/m          => 1
"foo" =~ /(?<=fo).*/m         => nil
This only seems to happen with singleline mode turned on (dot matches newline); without it, everything is OK:
"foo" =~ /(?<=f).*/           => 1
"foo" =~ /(?<=fo).*/          => 2
Tested on Ruby 1.9.3 and 2.0.0.
EDIT: Some more observations:
Adding an end-of-line anchor doesn't change anything:
"foo" =~ /(?<=fo).*$/m        => nil
But together with a lazy quantifier, it "works":
"foo" =~ /(?<=fo).*?$/m       => 2
EDIT: And some more observations:
.+ works as does its equivalent {1,}, but only in Ruby 1.9 (it seems that that's the only behavioral difference between the two in this scenario):
"foo" =~ /(?<=fo).+/m         => 2
"foo" =~ /(?<=fo).{1,}/       => 2
In Ruby 2.0:
"foo" =~ /(?<=fo).+/m         => nil
"foo" =~ /(?<=fo).{1,}/m      => nil
.{0,} is busted (in both 1.9 and 2.0):
"foo" =~ /(?<=fo).{0,}/m      => nil
But {n,m} works in both:
"foo" =~ /(?<=fo).{0,1}/m     => 2
"foo" =~ /(?<=fo).{0,2}/m     => 2
"foo" =~ /(?<=fo).{0,999}/m   => 2
"foo" =~ /(?<=fo).{1,999}/m   => 2
