How to curl an URL and saving output to a file using java

Question

I'm a newbie in java and need help in how to use the cURL in java and saving the output of the cURL command to a file in runtime.

Let's consider as i'm using the below URL which i have to cURL in the linux machine.

http://maniv.com/maniv/rest?method=sendMessage&msg_type=binary&parameter1=9999999&parameter2=9999999

When i'm hitting the above URL using curl "http://maniv.com/maniv/rest?method=sendMessage&msg_type=binary&parameter1=9999999&parameter2=9999999" in linux, it will give the ouput as:

Message | sent | successfully

Now i need to write the output into a new file based on the parameter1 as file name each time, when i change the parameter1 and hit the URL.

As of now I'm doing this in a shell script. But i need to do this in java and integrate in GUI. So, please give idea to do this. — dm90, Mar 06 '13 at 09:26

score 1 · Answer 1 · edited May 23 '17 at 10:30

1

Do you have to use curl command with Java? Could you use HttpClient to get html file? http://hc.apache.org/httpclient-3.x/

Please refer to this question: Read url to string in few lines of java code. It provides pretty good answer.

edited May 23 '17 at 10:30

Community

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1

answered Mar 06 '13 at 09:37

longhua

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Anything is fine.. I just need to code this. Since, i'm a newbie i just need idea for `HTTP` or `cURL` in java. – dm90 Mar 06 '13 at 09:43
This link maybe a proper place for you: http://docs.oracle.com/javase/tutorial/networking/urls/readingURL.html. All you need is to read html file from a URL. – longhua Mar 06 '13 at 09:46
Dude, mine is not a static URL. `http://maniv.com/maniv/rest?method=sendMessage&msg_type=binary&**parameter1=9999999**&**parameter2=9999999**`. The **PARAMETERT1** and **PARAMETER2** are the user inputs. So, in `URL oracle = new URL("http://www.oracle.com/");` i could not use. – dm90 Mar 06 '13 at 09:51
It seems that you are trying to make a POST operation: http://stackoverflow.com/questions/3324717/sending-http-post-request-in-java – longhua Mar 06 '13 at 09:56

score 1 · Accepted Answer · answered Mar 07 '13 at 06:51

Thanks for the effort. I got the answer after a long try! `

    String url = "http://maniv.com/maniv/rest";
    String charset = "UTF-8";
    String method = "sendMessage";
    String msg_type = "binary";
    String parameter1 = "9999999";
    String parameter2 = "0000000";
    String msg = "001100110001100011";

    // ...
    StringBuffer sb = null;
    String query = String
            .format("method=%s&msg_type=%s&userid=%s&password=%s&msg=%s",
                    URLEncoder.encode(method, charset),
                    URLEncoder.encode(msg_type, charset),
                    URLEncoder.encode(userid, charset),
                    URLEncoder.encode(password, charset),
                    URLEncoder.encode(msg, charset));
    try {
        URL requestUrl = new URL(url + "?" + query);
        HttpURLConnection conn = (HttpURLConnection) requestUrl.openConnection();
        conn.setDoOutput(true);
        conn.setRequestMethod("GET");
        OutputStreamWriter osw = new OutputStreamWriter(conn.getOutputStream());
        osw.write(query);
        osw.flush();
        BufferedReader br = new BufferedReader(new InputStreamReader(conn.getInputStream()));
        String in = "";
        sb = new StringBuffer();
        while ((in = br.readLine()) != null) {
            sb.append(in + "\n");
            System.out.println("Output:\n" +in);
        }
    } catch (Exception e) {
        System.out.println("Exception occured" + e);
    }
}

}`

How to curl an URL and saving output to a file using java

2 Answers2