Is it possible using a Windows batch file to determine if the version of Java (assuming 7) installed is the 32 bit version or the 64 bit version?
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Is it just that it is installed, or in the path as well. I have many versions installed to support different projects – Rob Goodwin Mar 07 '13 at 23:15
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2http://stackoverflow.com/a/2062263/1393766 – Pshemo Mar 07 '13 at 23:16
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@RobGoodwin assuming it is installed - it is which version it is. – hawkeye Mar 07 '13 at 23:20
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From what I've seen, most look for the existance of environment variables like JAVA_HOME – MadProgrammer Mar 07 '13 at 23:23
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@MadProgrammer so you're saying parse the JAVA_HOME based on whether it is in the 32 bit Program Files directory or not... – hawkeye Mar 07 '13 at 23:25
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@hawkeye That would one approach, but that will only tell you where `JAVA_HOME` points. You could also look at `ProgramFiles(x86)` and `ProgramFiles` to see if "Java\" exists – MadProgrammer Mar 07 '13 at 23:27
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@hawkeye You can have more than one. Are you interested in figuring this information out for all installations? – Rob Goodwin Mar 07 '13 at 23:30
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Here is a small windows script to get you started that will determine Java32 vs Java64 vs JavaNotInstalled.
Tweak as necessary...
@echo off
java -d64 -version >nul 2>&1
if errorlevel 1 goto maybe32bit
echo Java is 64 bit
goto EXIT
:maybe32bit
where java >nul 2>&1
if errorlevel 1 goto nojava
echo Java is 32 bit
goto EXIT
:nojava
echo Java is not installed
:EXIT
Java42
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@WestFarmer - Be more specific and perhaps open a question with the specific symptoms. Then, add a pointer here to the question. – Java42 May 29 '16 at 16:08
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Yes, it is possible. The bat file could run java -version and parse the output.
JB Nizet
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