Python lists are mutable objects, so when you do [[1]]*20 it creates one list object [1] and then places 20 references to it in the toplevel list.
As far as the mutability problem is concerned, this is the same as the following
a = [1,2,3]
b = a
b.append(4)
a # [1,2,3,4]
This happens because b=a merely copies the reference to the list instance from a to b. They are both referring to the same actual list.
In order to create a list of lists, like you tried above, you need to create a unique list for each entry. A list comprehension works nicely:
mainlist = [[1] for x in range(20)]
mainlist[0].append(2)
mainlist # [[1,2],[1],[1],...]
Edit
As an aside, since type names are metaclasses in Python, naming your variables by the type name is a bad idea.
The reason is that can cause several issues further down in the code:
a = range(3) # [0,1,2]
type(a) # (type 'list')
isinstance(a, list) # True
Now, create a variable named list
list = range(3)
list # [0,1,2]
isinstance(list, list)
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
TypeError: isinstance() arg 2 must be a class, type, or tuple of classes and types
Not to mention, now you cant use the list() operator
c = list((1,2,3))
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
TypeError: 'list' object is not callable