Servlet 3.0 API - Registering a servlet

Question

i am developing an example servlet on tomcat 7.0.37 & eclipse 3.7. My current problem is to get it runnable :(

//...imports and so on...

@WebServlet(value="/Hello")
public class AdminServlet extends HttpServlet
{
    private static final long serialVersionUID = -1139419481702036147L;

    @Override
    protected void doGet(HttpServletRequest req, HttpServletResponse resp)
            throws ServletException, IOException {
        super.doGet(req, resp);

        PrintWriter writer = resp.getWriter();
        writer.write("HelloWorld");
        writer.close();
    }
}

When I call the URL "http://localhost:8080/{webappname}/Hello" a window turned to "Status 404 - Resource not available". Is there anything wrong?

It is like in the most Servlet 3.0 examples :(

Are you sure the application has been deployed on the server and started ? — Apurv, Mar 29 '13 at 09:09

score 1 · Answer 1 · answered Mar 29 '13 at 09:14

1

Below are some of the causes:

Make sure your Servlet container supports Servlet 3.0. Most of them should support the,
Make sure your web.xml has version 3.0. For web.xml version < 3.0, the annotations may not get processed.
Make sure metadata-complete attribute is false. If it is true, the annotation may not get processed.

answered Mar 29 '13 at 09:14

Ramesh PVK

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The question says he's using Tomcat 7, so the first cause is already taken care of. – mthmulders Mar 29 '13 at 09:19
1

So, in general sense, it can be the next two causes. – Ramesh PVK Mar 29 '13 at 09:23

score 0 · Answer 2 · answered Mar 29 '13 at 09:14

0

Create {webappname}.war, put it in the webapps dir and restart the server.

answered Mar 29 '13 at 09:14

Roman C

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karthick · Answer 3 · 2013-03-29T09:56:22.387

0

The problem is you are not mapping the servlet to the correct url pattern. The servlet name should be mapped to the URl pattern. But in your code it's not done.

To do it correctly using annotations please see the following.

@WebServlet( name="AdminServlet", displayName="Admin Servlet", urlPatterns ={"/Hello","*.do"})
public class AdminServlet

edited Mar 29 '13 at 09:56

answered Mar 29 '13 at 09:23

karthick

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I installed only JDK 7 – George Krause Mar 29 '13 at 09:29
@GeorgeKrause: Make sure whether your Java_Home is pointing to that SDK and not the default JRE in your system. – karthick Mar 29 '13 at 09:35
It is pointing to SDK – George Krause Mar 29 '13 at 09:45
@GeorgeKrause: Found the issue. I have updated the answer – karthick Mar 29 '13 at 09:56

score 0 · Answer 4 · answered Mar 29 '13 at 10:25

0

I found my issue: I had to remove "super().doGet();"

answered Mar 29 '13 at 10:25

George Krause

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But how did it work without a proper url mapping? – karthick Mar 29 '13 at 10:42

Servlet 3.0 API - Registering a servlet

4 Answers4