When i write jQuery.fn.colorbox() it gives me same results as jQuery.colorbox(); I want to understand the significance of fn in jQuery.
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        sushil bharwani
        
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                    http://stackoverflow.com/about – Xotic750 May 11 '13 at 09:40
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            Last time I looked, fn was an alias for prototype in jquery.
Take a look at this stackexchange answer, it may give you some clarity.
 
    