How do I implement a keyup function with a dynamically create input element with JQuery?

Question

I can not figure out why the following code does not work. JSFIDDLE LINK

$(document).ready(function () {
    addInput();
});

var limit = 30;
function addInput() {
    var numberOfRows = $("#shipping tr").size();
    var id = numberOfRows;
    if (numberOfRows == limit) {
        alert("You have reached the limit of adding " + limit + " inputs");
    } else {
        $('#shipping').append('<tr id="rate' + id + '"></tr>');
        $('tr#rate' + id).append('<td></td>');
        $('tr#rate' + id).append('<td><input type="text" name="rate" /></td>');
    }
    $('input[name=rate]').on('keyup', 'input', function () {
        alert('YAY');
        return false;
    });
}

I am trying to assign a keyup function to the inputs that I add dynamically.

Expected output: YAY! inside a popup box

Please help!

see the demo in answer.. – Dipesh Parmar Apr 19 '13 at 03:40 — Dipesh Parmar, Apr 19 '13 at 03:40

score 7 · Accepted Answer · answered Apr 19 '13 at 03:41

7

Attach an keyup event handler to shipping table, and the event will bubble up from the input[name="rate"] to shipping table:

$('#shipping').on('keyup', 'input[name="rate"]', function () {
    alert('YAY');
    return false;
});

DEMO

answered Apr 19 '13 at 03:41

msapkal

8,268
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31
48

score 3 · Answer 2 · answered Apr 19 '13 at 03:36

3

You need to add delegation to document because its added to the document.

Example

$(document).on('keyup', 'input[name="rate"]', function () {
    alert('YAY ');
});

`Working Demo`

answered Apr 19 '13 at 03:36

Dipesh Parmar

27,090
8
61
90

It doesn't make sense to go up all the way to `document` when the `input[name="rate"]` elements are added to the `[id="shipping"]` element – Ian Apr 19 '13 at 04:51

How do I implement a keyup function with a dynamically create input element with JQuery?

2 Answers2

`Working Demo`

Linked