JavaScript split lookbehind

Question

I need to split a string by \.\s but leave the . appended to the array element.

Taking this string as a test, Lorem Ipusm. Excepteur sint occaecat. I need the output array to be:

[0] => Lorem Ipsum.
[1] => Excepteur sint occaecat.

See how the . still remains intact?

I believe I need a lookbehind regex because /\.(?=\s)*/ doesn't work, instead the . ends up at the beginning of each sentence after it.

Are you looking for this? http://stackoverflow.com/questions/4514144/js-string-split-without-removing-the-delimiters — AlessandroEmm, Apr 29 '13 at 12:43
Yeah I did, but I got an invalid capture group, or something? — James, Apr 29 '13 at 12:43
possible duplicate of [Javascript and regex: split string and keep the separator](http://stackoverflow.com/questions/12001953/javascript-and-regex-split-string-and-keep-the-separator) — mplungjan, Apr 29 '13 at 12:44
@TillHelge, JavaScript does not support Lookbehind assertions. — stema, Apr 29 '13 at 12:53
@stema Yeah...I just messed around with a jsfiddle and realized that by now. Never needed that before. Thanks for confiming my suspicion. ;) — Till Helge, Apr 29 '13 at 13:17

score 4 · Accepted Answer · answered Apr 29 '13 at 12:42

4

try this:

var s = "Lorem Ipsum. Excepteur sint occaecat.",
    parts = s.match(/(.+?\.(?:\s|$))/g); 
    // ["Lorem Ipsum. ", "Excepteur sint occaecat."]

answered Apr 29 '13 at 12:42

Fabrizio Calderan

Note the space at the end of the first result in array - but it is easy to take care of, though. – nhahtdh Apr 29 '13 at 12:45

1 Answers1