How should I type cast void *?

Question

I am learning C. I need to define a function to type cast the value of void * to the desired type. I'm not sure if I fully understand what I need to do. Here is my attempt. Can someone take a look and let me know if it's correct? If not, how should I fix it? Thank you in advance for your time.

void print_type(TYPE a)
{
    void *v_ptr;
    v_ptr = &a;

}

i am also not quite sure what it is you need to do, could you show the requirement? normally if you want to cast to another type from `void* ptr` to another type you just write `(type)ptr`. — AndersK, May 08 '13 at 20:21
See this question: http://stackoverflow.com/questions/2590314/what-are-the-reasons-for-casting-a-void-pointer — ollo, May 08 '13 at 20:24

score 5 · Answer 1 · edited May 23 '17 at 10:25

5

In C, void * is implicitly compatible with any data pointer type. If you have a POSIX implementation, then it's compatible with function pointers as well. There's no need for typecasting; conversely, it's even considered harmful.

edited May 23 '17 at 10:25

Community

1
1

answered May 08 '13 at 20:11

1

+1. I was also thinking about «value of void * to the desired type»... Not sure if just a bad description of a question about converting a pointer to `uintptr_t` or something like that :-> – May 08 '13 at 20:15
@VladLazarenko Thanks. Well, if I understood the question well, then this is all what OP is looking for... – May 08 '13 at 20:16

How should I type cast void *?

1 Answers1

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