C++ How to assign string as hexadecimal

Question

I got this string

0x3384BCFD
0x61CEB13B

both are of string type..

Initially I got this

uint32_t iv[2]  = {0xFFFFFFFF,0xFFFFFFAA};

How do I assign the 2 string above into iv[0] and iv[1]?

I want the final result of iv[2] as iv[2] = {0x3384BCFD,0x61CEB13B};

Thanks for helping!!

score 5 · Answer 1 · answered May 11 '13 at 17:35

5

Seeing as how this isn't in the linked dupe:

uint32_t iv[] = { //*cough* std::array exists as well
    std::stoul(strs[0], nullptr, 16), 
    std::stoul(strs[1], nullptr, 16)
};

answered May 11 '13 at 17:35

chris

This is probably the closest to what the OP wanted, he can use this in his array declaration. – Overv May 11 '13 at 17:36
@Overv, Good point. I'll actually add that. – chris May 11 '13 at 17:37

score 4 · Answer 2 · answered May 11 '13 at 17:35

4

Since it's C++ I suggest you to use streams with manipulators:

stringstream ss = stringstream("0x3384BCFD");
ss >> hex >> iv[0];

answered May 11 '13 at 17:35

Jack

David G · Accepted Answer · 2013-05-11T17:43:45.613

2

#include <sstream>

int main()
{
    uint32_t iv[2];

    std::stringstream("0x3384BCFD 0x61CEB13B") >> std::hex >> iv[0] >> iv[1];
}

edited May 11 '13 at 17:43

answered May 11 '13 at 17:37

David G

3 Answers3