Open Youtube Channel calling YouTube App (Android)

Question

I want to open YouTube App showing an specific channel, but this only execute the browser.

try 
        {
            Intent intent = new Intent(Intent.ACTION_VIEW);
            intent.setData(Uri.parse("http://www.youtube.com/"+channel));
            startActivity(intent);
        }
        catch (Exception e) 
        {
            startActivity(new Intent(Intent.ACTION_VIEW,Uri.parse("http://www.youtube.com/"+channel)));         
        }

I want to show this:

enter image description here

score 12 · Answer 1 · answered Feb 07 '16 at 13:44

12

Use this code it will open the channel

 startActivity(new Intent(Intent.ACTION_VIEW,   Uri.parse("http://www.youtube.com/channel/UCw7FqRl9XzrlB_D1vOg_Gyg")));

answered Feb 07 '16 at 13:44

Pir Fahim Shah

10,505
1
82
81

score 7 · Accepted Answer · answered May 13 '13 at 03:01

7

Do research on library called YouTubeAndroidPlayerApi. This piece of code does exactly what you want.

Intent intent = YouTubeIntents.createUserIntent(this, channelName);
startActivity(intent);

answered May 13 '13 at 03:01

Chor Wai Chun

3,226
25
41

1

It should be `YouTubeIntents.createChannelIntent(this, channelName);` for opening a youtube channel instead. – viper Jun 19 '17 at 11:35

score 1 · Answer 3 · answered Dec 28 '20 at 03:03

Check out my code for opening YouTube specific Channel:

//ID initialization
ImageView youtube = findViewById(R.id.youtubeID);

youtube.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View v) {

            String youtubeURL = "https://www.youtube.com/papelbd";
            Intent youtubeIntent=null;

            try {

                youtubeIntent=new Intent(Intent.ACTION_VIEW);
                youtubeIntent.setPackage("com.google.android.youtube");
                youtubeIntent.setData(Uri.parse(youtubeURL ));
                startActivity(youtubeIntent);

            } catch (ActivityNotFoundException e) {

                youtubeIntent= new Intent(Intent.ACTION_VIEW);
                youtubeIntent.setData(Uri.parse(youtubeURL ));
                startActivity(youtubeIntent);
            }
        }
    });

score 0 · Answer 4 · edited May 23 '17 at 11:46

0

Simply you can't. The image you linked, is about the YouTube application, not the website.

EDIT: Take a look here: Launch an application from another application on Android

edited May 23 '17 at 11:46

Community

1
1

answered May 12 '13 at 18:53

Bilbo Beggins

176
6

Sorry, I've probably spelled wrong... I want to open the app with X channel. – C4TInD May 12 '13 at 18:57

score 0 · Answer 5 · answered May 09 '19 at 14:32

Or, you could avoid the implementation of YouTubeAndroidPlayerApi Library: (kotlin)

const val URL_YOUTUBE = "https://www.youtube.com/channel/id"
const val URL_YOUTUBE_INAPP = "vnd.youtube.com/channel/id"

try{  
    //here we try to open the link in app
    startActivity(Intent(Intent.ACTION_VIEW, Uri.parse(URL_YOUTUBE_INAPP)))
}catch (e: Exception) {
   //the app isn't available: we open in browser`
   startActivity(Intent(Intent.ACTION_VIEW, Uri.parse(URL_YOUTUBE)))
}

score 0 · Answer 6 · answered Mar 16 '21 at 13:40

0

Follow this gist link below, If you face any trouble, just text me here.

https://gist.github.com/oalpayli/a25dca8dba396042b365af5bcf620393

answered Mar 16 '21 at 13:40

oalpayli

227
1
2
9

A link to a solution is welcome, but please ensure your answer is useful without it: [add context around the link](//meta.stackexchange.com/a/8259) so your fellow users will have some idea what it is and why it’s there, then quote the most relevant part of the page you're linking to in case the target page is unavailable. [Answers that are little more than a link may be deleted.](/help/deleted-answers) – STA Mar 16 '21 at 13:42

Open Youtube Channel calling YouTube App (Android)

6 Answers6

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