Work with append

Question

I have a number (nsteps) of groups of results (data). Each data has four subgroups of results (len(nodeSets)), one for each nodelabel.

I'd like to join in the same row the subgroups of results for each nodelabel. My code is like:

    for i in range(0,len(odb.rootAssembly.instances[myInstanceName].nodeSets['LOAD'].nodes)):
        for stepi in range(0, nsteps):
            stepName = odb.steps.values()[stepi].name 
            nodelabel = odb.rootAssembly.instances[myInstanceName].nodeSets['LOAD'].nodes[i].label
            hR='Node ' + myInstanceName + '.' +str(nodelabel)
            dCF3.append([odb.steps[stepName].historyRegions[hR].historyOutputs['CF3'].data])

My problem is that I get:

dCF3[0]=[[data in step1 for nodelabel 1]]
dCF3[1]=[[data in step2 for nodelabel 1]]
...
dCF3[n]=[[data in step1 for nodelabel 4]]
dCF3[n+1]=[[data in step2 for nodelabel 4]]

and I want:

dCF3[0]=[data in each stepi for nodelabel 1] #only one list
....
dCF3[3]=[data in each stepi for nodelabel 4] #only one list

Any ideas?

The question would be clearer if your code example actually made sense. — Matt Ball, May 16 '13 at 12:32

score 2 · Answer 1 · answered May 16 '13 at 12:37

2

Try something like:

for nodelabel in nodes:
    dCF3.append([data.stepi.nodelabel for stepi in range(0, nsteps)])

It would have been easier with some actual data to test the code with.

answered May 16 '13 at 12:37

Dek Dekku

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Added some code. I can add Data but it is too large – jpcgandre May 16 '13 at 15:05

Work with append

1 Answers1