How to convert hex string 'o\xf2\x00\x00' into a int32?

Question

When I read first 4 bytes with python code

len = fobj.read(4)

I got 'o\xf2\x00\x00'. This should be an int32, and when I read the file with other tool (matlab, for example), it gives 62063.

Could anybody give any hints on how I can convert the hex string into an int in python?

Thank you for any suggestion!

jamylak · Accepted Answer · 2013-05-17T08:57:36.213

7

>>> import struct
>>> struct.unpack('<i', 'o\xf2\x00\x00')
(62063,)

edited May 17 '13 at 08:57

answered May 17 '13 at 08:48

jamylak

@IgnacioVazquez-Abrams Made it explicitly little-endian now – jamylak May 17 '13 at 08:57
Thank you so much jamylak, for your prompt and helpful reply! – dehiker May 17 '13 at 09:16

score 1 · Answer 2 · answered Apr 01 '20 at 05:35

1

I Tried this and got the answer:

>>> print(int.from_bytes(b'o\xf2\x00\x00','little'))
62063

answered Apr 01 '20 at 05:35

JenilDave

2 Answers2