invalid use of template-name Queue without an argument list

Question

I'm getting a compile error that I can't figure out. It says:

Queue.h:18:23: error: invalid use of template-name â€˜Queueâ€™ without an argument list Queue.h:23:23: error: invalid use of template-name â€˜Queueâ€™ without an argument list

Can anyone help?

#if !defined QUEUE_SIZE
#define QUEUE_SIZE 30
#endif
using namespace std;

template <class TYPE> class Queue
{
 private:
  TYPE *array;
 public:
  Queue(Queue& other);
  Queue();
  ~Queue();
  Queue& operator=(Queue other);
  TYPE pushAndPop(TYPE x);
};

template <class TYPE> Queue::Queue()
{
  array=new TYPE[size];
}

template <class TYPE> Queue::~Queue()
{
  delete [] array;
}

You need to write `Queue::Queue` in the definition of the constructor. Similar for the destructor. — jogojapan, May 22 '13 at 05:07

score 2 · Accepted Answer · edited May 23 '17 at 12:29

Your syntax is slightly off. You need:

template <class TYPE> Queue<TYPE>::Queue()
{
...
}

template <TYPE>
Queue<TYPE>& operator=(Queue<TYPE> other) { ... }

Although note that you probably should be passing by const reference in most cases (certainly not by non-const reference):

template <TYPE>
Queue<TYPE>& operator=(const Queue<TYPE>& other) { ... }

Alternatively, you can inline the implementations:

template <class TYPE> class Queue
{
 private:
  TYPE *array;
 public:
  Queue(Queue& other);
  Queue() { array = new TYPE[size];}
  ~Queue() { delete [] array; }
  Queue& operator=(Queue other) { .... }
  TYPE pushAndPop(TYPE x) { .... }
};

Also, it is not a good idea to put using namespace std in a header file. In fact, it is not really a good idea to put it anywhere.

invalid use of template-name Queue without an argument list

1 Answers1

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