There is a problem with parsing a Url to a youtube video in my App.
Actually I should read video id from server then concatenate it with the ordinary link for youtube videos like this
the correct url is "https://www.youtube.com/watch?v=" + "Vuxmpogks64" the url after parsing when calling intent ONLY appear like http://www.youtube.com/watch?v= %EF%BB%BF Vuxmpogks64 and gives error video not found !
Why this part appear "%EF%BB%BF" ??
The code as follow
String myVideo = readAquaVideo();
        String[] ar = myVideo.split("[,]");
        video_id = ar[0];
        video_id = video_id.trim();
StringBuffer sb = new StringBuffer("");
        String url = "https://www.youtube.com/watch?v=";
        sb.append(url);
        sb.append(video_id);
        video_url = sb.toString().trim();
public static String readAquaVideo() {
        BufferedReader in = null;
        try {
            HttpClient client = new DefaultHttpClient();
            HttpGet request = new HttpGet();
            request.setURI(new URI("http://epic-demo.com/dunes/video.php"));
            HttpResponse response = client.execute(request);
            BufferedReader ien = new BufferedReader(new InputStreamReader(
                    response.getEntity().getContent()));
            StringBuffer sb = new StringBuffer("");
            String line = "";
            String NL = System.getProperty("line.separator");
            while ((line = ien.readLine()) != null) {
                sb.append(line + NL);
            }
            ien.close();
            video_id = sb.toString();
            video_id = video_id.trim();
            Log.d("parsing video",video_id);
        } catch (URISyntaxException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        } catch (ClientProtocolException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        } catch (IOException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        } finally {
            if (in != null) {
                try {
                    in.close();
                } catch (IOException e) {
                    e.printStackTrace();
                }
            }
        }
        return video_id;
        }
Intent intent = new Intent(Intent.ACTION_VIEW,Uri.parse(video_url));
startActivity(intent);