Shell script cut command

Question

I am trying to cut ABCservice and DEFService dfrom the array and print them.What am I missing here?

  urlArray=('http://server:port/ABCservice/services/ABCservice?wsdl' 'http://server:port/DEFservice/services/DEFservice?wsdl')   
        for url in "${urlArray[@]}"
         do
            service=echo $url|cut -f4 -d/
            echo $service
        done

Expected Output:

ABCService
DEFService

Current Output:

./test1.sh: line 6: http://server:port/ABCservice/services/ABCservice?wsdl: No such file or directory
./test1.sh: line 6: http://server:port/DEFservice/services/DEFservice?wsdl: No such file or directory

score 4 · Accepted Answer · answered May 30 '13 at 19:26

What abut this?

service=$(echo $url | cut -d"/" -f4)
echo $service

or directly

echo $(echo $url | cut -d"/" -f4)

The problems in your code:

service=echo $url|cut -f4 -d\

to save a command output in a variable, we do it like this: service=$(command).
your cut had \ as delimiter instead of /. Also it is good to wrap it with brackets: -d "/"

score 1 · Answer 2 · answered May 30 '13 at 19:27

1

service=$(echo $url | cut -d/ -f6 | cut -d\? -f1)
echo $service

answered May 30 '13 at 19:27

Adam Siemion

15,569
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score 1 · Answer 3 · answered May 30 '13 at 20:14

Using bash string function:

for i in "${!urlArray[@]}"; do 
    urlArray[i]="${urlArray[i]%\?*}"
    urlArray[i]="${urlArray[i]##*/}"
    echo ${urlArray[i]}
done



$ urlArray=('http://server:port/ABCservice/services/ABCservice?wsdl' 'http://server:port/DEFservice/services/DEFservice?wsdl') 
$ for i in "${!urlArray[@]}"; do urlArray[i]="${urlArray[i]%\?*}"; urlArray[i]="${urlArray[i]##*/}";  echo ${urlArray[i]} ; done
ABCservice
DEFservice

score 0 · Answer 4 · answered May 30 '13 at 19:26

0

Your delimiter should be a forward slash

echo 'http://server:port/ABCservice/services/ABCservice?wsdl' | cut -f 4 -d/

answered May 30 '13 at 19:26

Thomas Fenzl

4,342
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score 0 · Answer 5 · edited Feb 24 '14 at 08:26

0

The \ is an escape character. Try \\ instead.

edited Feb 24 '14 at 08:26

zessx

68,042
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answered May 30 '13 at 19:27

beiller

3,105
1
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1

To avoid espacing chars, use backquotes `\`` instead of double quotes `"`. – zessx Feb 24 '14 at 08:26

Shell script cut command

5 Answers5