Get last ajax call in jquery

Question

I want to get last ajax call made in my code .

here is my code

<!DOCTYPE html>
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<title></title>
<script src="Scripts/jquery-1.7.1.min.js"></script>


<script>
    function getCreateAccount() {
        $.ajax({
             type: "GET",
             url: "/Account/Register/",
             contentType: "application/json; charset=utf-8",
             dataType: "json"
         });
        console.log($.ajax.mostRecentCall.args[0]);
    }

</script>

</head>
<body>

</body>
</html>

but when i see in my console it says "TypeError: $.ajax.mostRecentCall is undefined" .

Thanks,

use `var ajaxcall = $.ajax({ type: "GET", ...` and try if you can use the ajaxcall variable to get the information you need — bart s, Jun 06 '13 at 08:32
Is this post of any help? http://stackoverflow.com/questions/4176956/get-latest-ajax-request-and-abort-others — Pradeep, Jun 06 '13 at 08:33
do you want to know the most recent _initiated_ call, or the most recently _completed_ ? — Alnitak, Jun 06 '13 at 08:37
I am working with jasmine , and this thing works perfectly in jasmine , but i want to get the same thing out of jasmine — Ancient, Jun 06 '13 at 08:38
@user2413182 and you're trying to replicate the Jasmine functionality, without using Jasmine? — Alnitak, Jun 06 '13 at 08:45

score 8 · Accepted Answer · edited Jul 15 '15 at 17:17

8

You may register a global ajaxComplete handler that will be invoked every time an AJAX call finishes.

With this, you can emulate something like the Jasmine $.ajax.calls.mostRecentCall() property:

$(document).ajaxComplete(function(ev, jqXHR, settings) {
    $.ajax.mostRecentCall = jqXHR;
});

In this case I'm saving the jqXHR object, rather than the exact set of parameters that was passed to $.ajax.

Note, of course, that this won't be populated immediately after $.ajax is called - it won't be filled until at least one call has finished.

edited Jul 15 '15 at 17:17

camiblanch

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answered Jun 06 '13 at 08:40

Alnitak

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No no no! If you initialise Jasmine properly, and call spyOn($, "ajax") beforehand, then it should work without any hacks! – jackocnr Apr 24 '14 at 18:58
1

@jackocnr note that the OP said they wanted to get this functionality _without_ using Jasmine. – Alnitak Feb 09 '18 at 00:27

score 3 · Answer 2 · answered Jun 06 '13 at 08:41

3

I think mostRecentCall function is from Jasmine framework. You must include Jasmine in your code.

mostRecentCall does not exist in jquery!

answered Jun 06 '13 at 08:41

Sharky

6,154
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score 0 · Answer 3 · answered Jun 06 '13 at 08:37

0

there is no such this like "$.ajax.mostRecentCall" in ajax jquery.

As PSR mentioned you could try to use a flag variable

answered Jun 06 '13 at 08:37

user23031988

330
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can you put something on fiddle ? – Ancient Jun 06 '13 at 08:39

score 0 · Answer 4 · answered Jun 06 '13 at 08:41

0

Adding an alert before logging will give enough time for the ajax call to be finished.(that should do the trick)

if you don't want any alerts then you can use sleep() method

answered Jun 06 '13 at 08:41

Chakradhar Vyza

285
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score 0 · Answer 5 · answered Jun 06 '13 at 08:47

There is nothing like

$.ajax.mostRecentCall

in Jquery. That is from Jasmine.js. Unless and until you add reference to Jasmine.js and follow the steps to spy on function, it will give you an error.

You may want to refer the documentation of Jasmin.js. Here's the link that shows how to use it.

Get last ajax call in jquery

5 Answers5