I'm trying to check for the existence of an executable on a remote machine, then run said executable. To do so I'm using subprocess to run ssh <host> ls <file>, and if that's successful, run ssh <host> <file>. ssh asks for a password, of course, and I'd like to provide that automatically. Also, I'd like to get the returncode from ls, and stdout and stderr from running the command.
So I know the communicate() method is needed, to avoid deadlocks, but I can't get the password to be recognized by Popen(stdin). Also I'm using Python 2.4.3, and stuck on that version.  Here's the code I've got so far:
import os  
import subprocess as sb  
def WallHost(args):  
    #passwd = getpass.getpass()  
    passwd = "password"  
    for host in args:   
        # ssh to the machine and verify that the script is in /usr/bin   
        sshLsResult = sb.Popen(["ssh", host, "ls", "/usr/bin/wall"], stdin=sb.PIPE, stderr=sb.PIPE, stdout=sb.PIPE)  
        (sshLsStdout, sshLsStderr) = sshLsResult.communicate(input=passwd)  
        sshResult = sshLsResult.returncode  
        if sshResult != 0:                      
            raise "wall is not installed on %s. Please check." % host  
        else:  
            sshWallResult = sb.Popen(["ssh", host, "/usr/bin/wall", "hello world"], stdin=sb.PIPE, stderr=sb.PIPE, stdout=sb.PIPE)  
            (sshWallStdout, sshWallStderr) = sshWallResult.communicate(input=passwd)  
            print "sshStdout for wall is \n%s\nsshStderr is \n\n" % (sshWallStdout, sshWallStderr)  
args = ["127.0.0.1", "192.168.0.1", "10.10.265.1"]  
WallHost(args)  
Any help getting the process to accept that password is appreciated. Or if you've got a better way to check for the executable and then run it on a remote host. ;)
thx anthony
 
     
    