8

I am using android 4.1.1 ... I am making an application that allows the user to make his own network using Wifi Hotspot and then the clients can connect to it and share data. I have successfully created the Wifi hotspot in android but I cannot configure it for the purpose. Is there any way to configure Wifi Hotspot on android through coding ??

Mike Strobel
  • 25,075
  • 57
  • 69
Khan Umair
  • 81
  • 1
  • 1
  • 2

2 Answers2

16

This answer maybe outdated!

if(wifiManager.isWifiEnabled())
{
    wifiManager.setWifiEnabled(false); 
}

WifiConfiguration netConfig = new WifiConfiguration();

netConfig.SSID = "MyAP";
netConfig.allowedAuthAlgorithms.set(WifiConfiguration.AuthAlgorithm.OPEN);
netConfig.allowedProtocols.set(WifiConfiguration.Protocol.RSN);
netConfig.allowedProtocols.set(WifiConfiguration.Protocol.WPA);
netConfig.allowedKeyManagement.set(WifiConfiguration.KeyMgmt.NONE);

try{
    Method setWifiApMethod = wifiManager.getClass().getMethod("setWifiApEnabled", WifiConfiguration.class, boolean.class);
    boolean apstatus=(Boolean) setWifiApMethod.invoke(wifiManager, netConfig,true);

    Method isWifiApEnabledmethod = wifiManager.getClass().getMethod("isWifiApEnabled"); 
    while(!(Boolean)isWifiApEnabledmethod.invoke(wifiManager)){};
    Method getWifiApStateMethod = wifiManager.getClass().getMethod("getWifiApState"); 
    int apstate=(Integer)getWifiApStateMethod.invoke(wifiManager);
    Method getWifiApConfigurationMethod = wifiManager.getClass().getMethod("getWifiApConfiguration");
    netConfig=(WifiConfiguration)getWifiApConfigurationMethod.invoke(wifiManager);
    Log.e("CLIENT", "\nSSID:"+netConfig.SSID+"\nPassword:"+netConfig.preSharedKey+"\n");

} catch (Exception e) {
    Log.e(this.getClass().toString(), "", e);
}
mizdler
  • 621
  • 4
  • 8
  • Is there any `setWifiApConfiguration` for this Wifi HotSpot so I can connect to custom wifi access point using code. – zionpi Jun 28 '16 at 03:48
  • Doesn't work on Android 6 and 5.1 above. I have added the ACTION_MANAGE_WRITE_SETTINGS permission but still getting error as `Exception in softap start java.lang.IllegalStateException: command '2707 softap set wlan0 ....` – AkshayT Jan 30 '17 at 09:46
  • @AkshayTaru No surprise! at the time I answered the latest version of android was 5.0 , I hope you can update the answer. – mizdler Jan 31 '17 at 20:31
0

Here is a possible solution:

private WifiManager.LocalOnlyHotspotReservation mReservation;

 WifiManager wifiManager = (WifiManager) getApplicationContext().getSystemService(Context.WIFI_SERVICE);

wifiManager.startLocalOnlyHotspot(new WifiManager.LocalOnlyHotspotCallback() {

        @Override
        public void onStarted(WifiManager.LocalOnlyHotspotReservation reservation) {
            super.onStarted(reservation);
            mReservation = reservation;
        }

        @Override
        public void onStopped() {
            super.onStopped();
        }

        @Override
        public void onFailed(int reason) {
            super.onFailed(reason);
        }
    }, new Handler());
double-beep
  • 5,031
  • 17
  • 33
  • 41
tushar
  • 36
  • 4
  • While this code may answer the question, providing additional context regarding why and/or how this code answers the question improves its long-term value. – double-beep Dec 29 '18 at 17:30