Destroy session variable when JS function being called

Question

i have made a function destroy() that is being called onclick event of logout button. But the problem is server side code in that function being always called on page load whether the logout button being clicked or not. All i want to do is to set a value for session varaible lastVisit onclick event of logout button. Kindly let me know what is an appropriate way to do it thanks,

              function destroy()
                {
                <?php $_SESSION['lastVisit'] = "logout"; ?>
                alert('hi');

                }

PHP is executed server-side, _JavaScript_ is executed client side, when a page is generated, it's server side, when a page is viewed (and _JavaScript_ run), it's client side. — Paul S., Jun 30 '13 at 16:39
@PatrickEvans thanks for clearing my confusion, kindly let me know how can i set a value for session varaible lastVisit onclick event of logout button — user2304394, Jun 30 '13 at 16:43
@paka hmm i can use cookies. So how to destroy the cookie named `lastVisit` — user2304394, Jun 30 '13 at 16:45
@user2304394 try this http://stackoverflow.com/questions/2144386/javascript-delete-cookie — paka, Jun 30 '13 at 16:47

Patrick Evans · Accepted Answer · 2013-06-30T17:23:28.823

2

You are mixing php code with javascript code they dont work together like that you will need to do an ajax call and this is made easy since you are using jQuery.

Javascript

jQuery(document).ready(function() {
   jQuery("#LogoutButtonID").click(destroy());
});
function destroy() {
   jQuery.ajax({
      "url":"http://www.example.com/someScriptToLogout.php",
      "success":function() {
         alert("i logged out");
      }
   });
}

and in someScriptToLogout.php

<?php
session_start();
$_SESSION['lastVisit'] = "logout";

edited Jun 30 '13 at 17:23

answered Jun 30 '13 at 16:44

Patrick Evans

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2

Don' forget `session_start()` :) – moonwave99 Jun 30 '13 at 16:48
@moonwave99, oh yes i did seem to forget that didnt i :) – Patrick Evans Jun 30 '13 at 17:23

score 1 · Answer 2 · answered Jun 30 '13 at 16:49

Why not go the Ajax way?

PHP:

if(isset($_POST['endSession'])){
destroy();

echo 'Hi';
}

function destroy(){
  $_SESSION['lastVisit'] = "logout"; 
                }

javascript:

$.post('logOut.php',{endSession:'yes'},function(hi){

alert(hi)

})

That for sure will do what you want

Please note: This solution will assume that you have jQuery in your page and that your php codes are in a page named logOut.php

Destroy session variable when JS function being called

2 Answers2