Read Information from .XML file

Question

Imagine i have .xml file with the below format.

<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<config>
    <Directory>c:/test</Directory>
    <headerLine>1</headerLine>
    <pattern>.*\.txt</pattern>
</config>

The <Directory> tag, Specify the path of the file.

The <headerLine> tags, specify how many lines of my file have a header and the other is Body.(Not Important)

The <pattern> tags. specify the Format of the files.

the question is:

i want to read a file. first of all, i have to go to <Directory> tag, and get the directory of my files, then i have to read all of the files in that directory with the specify pattern, that shows in tags. for example .in C:/test , i have many file, but i should read files, that terminated with ".*.txt" . i use "Unmarshal" algorithm to read from .xml and convert it to java object. my problem, is how can i defind to read all of the files in c:/test directory with that pattern. could you please help me, how can i solve this problem?

FileSplitter fileSplitter = new FileSplitter("C:\\test.txt");

with this code, i can read just test.txt file, but i want to read directories with specific pattern.

There are many method to read XML. Use DOM, SAX etc. For details http://docs.oracle.com/javase/tutorial/jaxp/ — Masudul, Jul 01 '13 at 08:07
Try this for reading files from directory http://stackoverflow.com/a/5924345/1862502 — Vignesh Vino, Jul 01 '13 at 08:09
You can just use FilenameFilter as @VigneshVino suggested. Nothing is keeping you from using a regular expression in the `accept()` method. — secra, Jul 01 '13 at 13:59

score 0 · Accepted Answer · answered Jul 08 '13 at 06:11

Yes, That,s right. as what is "Vignesh Vino" suggested, this code, solve my problem and answer my question

File folder = new File("/path/to/files");
File[] listOfFiles = folder.listFiles();

for (int i = 0; i < listOfFiles.length; i++) {
  File file = listOfFiles[i];
  if (file.isFile() && file.getName().endsWith(".txt")) {
    String content = FileUtils.readFileToString(file);
    /* do somthing with content */
  } 
}

Read Information from .XML file

1 Answers1