Need EqualIgnoreCase when getting index

Question

String s ="Ganesh";

System.out.println(""+s.indexOf("ga"));
System.out.println(""+s.indexOf("Ga"));

When I run this, I get -1 for s.indexOf("ga") and 0 for s.indexOf("Ga")

I want to get 0 for both.

How to achieve this?

score 2 · Answer 1 · answered Jul 04 '13 at 07:34

2

Unfortunately, there is no indexOfIgnoreCase() method, but you can achieve the same with using toLowerCase().

System.out.println(""+s.toLowerCase().indexOf("ga"));

answered Jul 04 '13 at 07:34

Buhake Sindi

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Uwe Plonus · Answer 2 · 2013-07-04T07:47:48.157

1

To use indexOf case-insensitive you can convert the Strings to lowercase first:

System.out.println("" + s.toLowerCase().indexOf("ga".toLowerCase()));
System.out.println("" + s.toLowerCase().indexOf("Ga".toLowerCase()));

edited Jul 04 '13 at 07:47

answered Jul 04 '13 at 07:35

Uwe Plonus

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I think it's toLowerCase.. Can't edit due to some restrictions – Harshavardhan Konakanchi Jul 04 '13 at 07:42

score 1 · Answer 3 · answered Jul 04 '13 at 07:35

1

use the toLowerCase() or the toUpperCase() method of the String class, before you use the indexOf().

answered Jul 04 '13 at 07:35

htz

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score 1 · Accepted Answer · answered Jul 04 '13 at 07:37

You can convert the string you're looking for to lower or upper case when using indexOf, this way you'll always get the correct index regardless of casing

String s = "Ganesh";
String s2 = "ga";
String s3 = "Ga";

System.out.println(s.toLowerCase().indexOf(s2.toLowerCase()));
System.out.println(s.toLowerCase().indexOf(s3.toLowerCase()));

> 0
> 0

You can even put it into your own method like this:

public int indexOfIgnoreCase(String s, String find) {
    return s.toLowerCase().indexOf(find.toLowerCase());
}

Then you can use it like this:

String s = "Ganesh";

System.out.println(indexOfIgnoreCase(s, "ga"));
System.out.println(indexOfIgnoreCase(s, "Ga"));

> 0
> 0

Need EqualIgnoreCase when getting index

4 Answers4