How to wait until only the first thread is finished in Python

Question

The requirement is to start five threads, and wait only in the fastest thread. All five threads went to look for the same data 5 directions, and one is enough to continue the control flow.

Actually, I need to wait for the first two threads to return, to verify against each other. But I guess if I know how to wait for the fastest. I can figure out how to wait for the second-fastest.

A lot talk about join(timeout), but you don't know in advance which one to wait (which one to apply join in advance).

Answer 1

Use a queue: each thread when completed puts the result on the queue and then you just need to read the appropriate number of results and ignore the remainder:

#!python3.3
import queue    # For Python 2.x use 'import Queue as queue'
import threading, time, random

def func(id, result_queue):
    print("Thread", id)
    time.sleep(random.random() * 5)
    result_queue.put((id, 'done'))

def main():
    q = queue.Queue()
    threads = [ threading.Thread(target=func, args=(i, q)) for i in range(5) ]
    for th in threads:
        th.daemon = True
        th.start()

    result1 = q.get()
    result2 = q.get()

    print("Second result: {}".format(result2))

if __name__=='__main__':
    main()

Documentation for Queue.get() (with no arguments it is equivalent to Queue.get(True, None):

Queue.get([block[, timeout]])

Remove and return an item from the queue. If optional args block is true and timeout is None (the default), block if necessary until an item is available. If timeout is a positive number, it blocks at most timeout seconds and raises the Empty exception if no item was available within that time. Otherwise (block is false), return an item if one is immediately available, else raise the Empty exception (timeout is ignored in that case).

Answer 2

If you have some sort of processing loop in your threads, the following code will terminate them when one terminates by using a threading.Event():

def my_thread(stop_event):
    while not stop_event.is_set():
        # do stuff in a loop

        # some check if stuff is complete
        if stuff_complete:
            stop_event.set()
            break

def run_threads():
    # create a thread event
    a_stop_event = threading.Event()

    # spawn the threads
    for x in range(5):
        t = threading.Thread(target=my_thread, args=[a_stop_event])
        t.start()

    while not a_stop_event.is_set():
        # wait for an event
        time.sleep(0.1)

    print "At least one thread is done"

If your process is "cheap" or a single request-response type thread (i.e. for instance an async HTTP request) then Duncan's answer is a good approach.

Answer 3

You can use an event for this. See http://docs.python.org/2/library/threading.html#event-objects The idea is that the worker threads raise an event when they are finished. The main thread waits for this event before continueing. The worker thread can set a (mutexed) variable to identify itself with the event.

Answer 4

Duncan's method is probably the best and is what I would recommend. I've been mildly annoyed by the lack of "wait for next completed thread to complete" before, though, so I just wrote this up to try it out. Seems to work. Simply use MWThread in place of threading.thread and you get this new wait_for_thread function.

The global variables are a bit klunky; an alternative would be to make them class-level variables. But if this is hidden in a module (mwthread.py or whatever) it should be fine either way.

#! /usr/bin/env python

# Example of how to "wait for" / join whichever threads is/are done,
# in (more or less) the order they're done.

import threading
from collections import deque

_monitored_threads = []
_exited_threads = deque()
_lock = threading.Lock()
_cond = threading.Condition(_lock)

class MWThread(threading.Thread):
    """
    multi-wait-able thread, or monitored-wait-able thread
    """
    def run(self):
        tid = threading.current_thread()
        try:
            with _lock:
                _monitored_threads.append(tid)
            super(MWThread, self).run()
        finally:
            with _lock:
                _monitored_threads.remove(tid)
                _exited_threads.append(tid)
                _cond.notifyAll()

def wait_for_thread(timeout=None):
    """
    Wait for some thread(s) to have finished, with optional
    timeout.  Return the first finished thread instance (which
    is removed from the finished-threads queue).

    If there are no unfinished threads this returns None
    without waiting.
    """
    with _cond:
        if not _exited_threads and _monitored_threads:
            _cond.wait(timeout)
        if _exited_threads:
            result = _exited_threads.popleft()
        else:
            result = None
    return result

def main():
    print 'testing this stuff'
    def func(i):
        import time, random
        sleeptime = (random.random() * 2) + 1
        print 'thread', i, 'starting - sleep for', sleeptime
        time.sleep(sleeptime)
        print 'thread', i, 'finished'

    threads = [MWThread(target=func, args=(i,)) for i in range(3)]
    for th in threads:
        th.start()
    i = 0
    while i < 3:
        print 'main: wait up to .5 sec'
        th = wait_for_thread(.5)
        if th:
            print 'main: got', th
            th.join()
            i += 1
        else:
            print 'main: timeout'
    print 'I think I collected them all'
    print 'result of wait_for_thread():'
    print wait_for_thread()

if __name__ == '__main__':
    main()

Answer 5

Or just keep track of all finished threads in a list and let the second thread to finish handle whatever is supposed to be done, Python lists are threadsafe.

finished_threads = []
event = threading.Event()

def func():
   do_important_stuff()

   thisthread = threading.current_thread()
   finished_threads.append(thisthread)
   if len(finished_threads) > 1 and finished_threads[1] == thisthread:
       #yay we are number two!
       event.set()

for i in range(5):
    threading.Thread(target=func).start()

event.wait()

Answer 6

I think if you want to wait you should use the time library. console:

pip install time

code:

import time
time.Sleep(5)#seconds