I'm using system() to open and close an external program with which my code communicates. However, every time I use the system() function, I get the console output I would get if I was calling the program from a normal terminal/shell, e.g. every time I call system(killall [program] &) I get a Terminated message. Is there a way to suppress this type of outputs?
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joaocandre
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3Redirect their output to `/dev/null`, as always. – Jon Jul 10 '13 at 20:40
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@Jon I'm already trying that, but I still get "Terminated" messages on the console. – joaocandre Jul 22 '13 at 10:24
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Problem is, with `execlp` I have I get stuck waiting for the command to finish; What I was looking for was something that would allow me to just start a second process, that runs in parallel with the main program, like I get with `system("[program] &")` – joaocandre Jul 22 '13 at 11:11
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@joaocandre you should use [std::thread](http://en.cppreference.com/w/cpp/thread/thread). See the accepted answer [here](http://stackoverflow.com/questions/266168/simple-example-of-threading-in-c), put your `execlp` in `task1`. This should do the trick. – dotixx Jul 22 '13 at 11:39
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Apparently, using `task1.join()` implies waiting for `task1` to finish, so it's not quite what I am looking for. – joaocandre Jul 22 '13 at 16:17
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@joaocandre just don't call `join()`, the task1 should be executed at the same time without blocking your main thread. – dotixx Jul 22 '13 at 16:52
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not using `join()` results in `task1` not being lauched at all. I've also tried using `detach` same result. – joaocandre Jul 23 '13 at 10:04