Connect mysqli without print error

Question

Is any way to call new mysqli($host, $user, $pass, $db_name) without printing the following errors?

Warning: mysqli::mysqli(): (28000/1045): Access denied for user 'user'@'127.0.0.1' (using password: YES) in...

I don't like to ignore errors (@ or error_reporting(0)), i would like any other "better practice" way.

I don't understand.. you don't want to see an error saying your access to the database is denied?? A better practice would be to write the code so that no warning is printed — Sterling Archer, Jul 14 '13 at 18:22
I would imagine that you are trying to check if a connection can be made, and if not, load the page another way instead, but the warning gets in the way. Am I correct? — 3ventic, Jul 14 '13 at 18:26
@3ventic That is a solution, check if the connection is possible before trying to connect, if possible then connect, if not get the error it would give (Ex.: Wrong password) and send it to my error handler. But never print it. — Miawa, Jul 14 '13 at 18:40

Your Common Sense · Accepted Answer · 2013-07-14T18:49:47.797

0

Well if you don't want errors to be printed - just tell PHP not to print them.
Configure PHP this way:

display_errors = 0
log_errors = 1

if you want to catch errors in some handler, you have to register it first.

edited Jul 14 '13 at 18:49

answered Jul 14 '13 at 18:26

Your Common Sense

I don't want to ignore every error, i use an ErrorHandler class, so if the password is wrong i will send the error "Wrong password" to my handler – Miawa Jul 14 '13 at 18:43
Now i have a noob question for you: When i set "display_errors = 0" on my PHP configuration i can still handle them with my handler? – Miawa Jul 14 '13 at 19:11
Yes, this is irrelevant matters. – Your Common Sense Jul 15 '13 at 05:23

1 Answers1