Splitting characters in string

Question

I have a string such as '01301347' and I want to split it into something like '01-13-30-01-13-34-47'.

Is it possible to do something like this using split()?

look here: http://stackoverflow.com/questions/9475241/split-python-string-every-nth-character?rq=1 — astrognocci, Jul 15 '13 at 20:22
Split should be used for finding letters or numbers, and it is an inefficient process so try not to use it when you can do something else. — debianplebian, Jul 15 '13 at 20:25

score 3 · Answer 1 · answered Jul 15 '13 at 20:22

3

You want to splice and join, not split:

'-'.join(mystr[i:i+2] for i in xrange(0, len(mystr)-1))

You could also use itertools.islice and itertools.izip:

'-'.join((a+b for a,b in itertools.izip(mystr, itertools.islice(mystr, 1, len(mystr)))))

answered Jul 15 '13 at 20:22

inspectorG4dget

Rohit Jain · Answer 2 · 2013-07-15T20:30:14.297

1

>>> s = '01301347'
>>> '-'.join(s[i:i+2] for i in range(0, len(s) - 1))
'01-13-30-01-13-34-47'

or you can use:

>>> '-'.join(a+b for a,b in zip(s, s[1:]))
'01-13-30-01-13-34-47'

edited Jul 15 '13 at 20:30

answered Jul 15 '13 at 20:23

Rohit Jain

score 0 · Answer 3 · answered Jul 15 '13 at 20:43

>>> from operator import add
>>> from itertools import starmap
>>> '-'.join(starmap(add,zip(*[iter(s)]*2)))
'01-30-13-47'

>>> zip(*[iter(s)]*2)
[('0', '1'), ('3', '0'), ('1', '3'), ('4', '7')]

add is equivalent for +: a + b = add(a,b)

starmap applies function to unpacked list of arguments from each value from iterable.

>>> list(starmap(add,zip(*[iter(s)]*2)))
['01', '30', '13', '47']

Lastly we just join them:

>>> '-'.join(starmap(add,zip(*[iter(s)]*2)))
'01-30-13-47'

By the way, we can avoid having to use starmap and add by writing it in a bit different way:

>>> '-'.join(map(''.join,zip(*[iter(s)]*2)))
'01-30-13-47'

3 Answers3