got Notice message when submit form in html

Question

<html>
<body>
  <form action="" method="GET">
  Name: <input type="text" name="name" />
  Age: <input type="text" name="age" />
  <input type="submit" />
  </form> 
</body>
</html>
<?php
  if( $_GET["name"] || $_GET["age"] )
  {
     echo "Welcome ". $_GET['name']. "<br />";
     echo "You are ". $_GET['age']. " years old.";
  }
?>

Question:

when I open above script in browser, It shows:Notice: Undefined index: name in D:\wamp\www\oop\test3.php on line 13, I know if is because the form is not submit yet, so $_GET["name"] does not exist, but how to fix this problem?

possible duplicate of [Reference - What does this error mean in PHP?](http://stackoverflow.com/questions/12769982/reference-what-does-this-error-mean-in-php) — kittycat, Jul 20 '13 at 03:59

score 1 · Accepted Answer · answered Jul 20 '13 at 03:02

Just set the name of the submit button, and use isset() to check if the form was submitted.

<html>
    <body>
      <form action="" method="GET">
          Name: <input type="text" name="name" />
          Age: <input type="text" name="age" />
          <input type="submit" name="submit" />
      </form> 
    </body>
</html>

<?php
    if( isset($_GET['submit']) )
    {
        echo "Welcome ". $_GET['name']. "<br />";
        echo "You are ". $_GET['age']. " years old.";
    }
?>

Funk Forty Niner · Answer 2 · 2013-07-20T03:58:33.830

The example below will check if both fields are filled.

If one or the other is not filled, an error message will appear.

If both are filled, then the user will see:

Welcome Bob // assuming the person's name is "Bob" in the field.
You are 30 years old. // assuming the person entered "30" in the field.

Otherwise, it will echo:

Fill in all fields.

Here is the example below:

<html>
    <body>
      <form action="" method="GET">
          Name: <input type="text" name="name" />
          Age: <input type="text" name="age" />
          <input type="submit" name="submit" />
      </form> 
    </body>
</html>

<?php


if($_GET['name'] && $_GET['age'])

    {
        echo "Welcome ". $_GET['name']. "<br />";
        echo "You are ". $_GET['age']. " years old.";
    }

if(!$_GET['name'] || !$_GET['age'])

    {

        echo "Fill in all fields";

    }

?>

I've made use of both && and || logical operators for validation.

Consult the PHP manual for more information: http://php.net/manual/en/language.operators.logical.php

score 0 · Answer 3 · answered Jul 20 '13 at 03:02

0

You can test if your particular _GET variable exists. For example:

<?php
if ( isset ( $_GET["name"] ) ) {
    echo "Welcome ". $_GET['name']. "<br />";          
}
?>

answered Jul 20 '13 at 03:02

Ryan

26,884
9
56
83

score -1 · Answer 4 · answered Jul 20 '13 at 03:01

-1

Try:

<form action="" method="GET">
Name: <input type="text" name="name" id="name" />
Age: <input type="text" name="age" id="age" />
<input type="submit" />
</form>

answered Jul 20 '13 at 03:01

Ricky Nelson

876
10
24

2

How does adding an ID change anything server side? – Austin Brunkhorst Jul 20 '13 at 03:02
I was thinking the problem was with the form variable. No need to get all crazy with a down vote, it was just something to try. – Ricky Nelson Jul 20 '13 at 03:28

got Notice message when submit form in html

4 Answers4