Why is there a difference in output?

Question

class Amie
{
   public static void main(String...a)
   {
       int i=5;
       i=++i/i++;
       SOP(i);
   }
}

OUTPUT=1

in C ---

void main()
{
    int i=5;
    i=++i/i++;
    printf(i);
}

OUTPUT = 2

Please refer http://stackoverflow.com/questions/4176328/undefined-behavior-and-sequence-points. This explains the behaviour of such expresssions in C — Vivek Maran, Jul 20 '13 at 12:32
`undefined behavior` and `== vs equals` are the most two duplicated questions here :_( — Maroun, Jul 20 '13 at 12:33
This is probably a better dup: http://stackoverflow.com/questions/18402304/please-explain-why-java-and-c-give-different-answers-for-this-code — Shafik Yaghmour, Aug 29 '13 at 15:08

score 0 · Answer 1 · answered Jul 20 '13 at 12:33

Java standard does reglament how such an expression should be evaluated and there is only 1 possible answer - 1.

In case of C there is no guarantee from standard for possible optimization. You could receive 2 as well as 1 in executables generated by other compilers. So it is undefined behaviour in C

Why is there a difference in output?

1 Answers1