I was trying to convert a BufferedImage's byte[] from 32-bit RGBA to 24-bit RGB. According to this answer the fastest way to get the byte[] from the image is:
byte[] pixels = ((DataBufferByte) bufferedImage.getRaster().getDataBuffer()).getData();
So I iterate over all bytes assuming their order is R G B A and for every 4 bytes, I write the first 3 in an output byte[] (i.e. ignoring the alpha value).
This works fine when run from Eclipse and the bytes are converted correctly. However when I run the same program from the command line the same bytes are returned with the opposite byte order!
The test image I use for my test is a 5x5 black image where only its top-left corner is different having the RGBA color [aa cc ee ff]:  
 
And a zoomed-in version for conveniency:

My folder structure is:
- src/  
  - test.png
  - test/
      - TestBufferedImage.java  
The SSCCE is the following:
package test;
import java.awt.image.BufferedImage;
import java.awt.image.DataBufferByte;
import java.io.IOException;
import java.io.InputStream;
import javax.imageio.ImageIO;
public class TestBufferedImage {
  private static void log(String s) {
    System.out.println(s);
  }
  private static String toByteString(byte b) {
    // Perform a bitwise AND for convenience while printing. 
    // Otherwise Integer.toHexString() interprets values as integers and a negative byte 0xFF will be printed as "ffffffff"
    return Integer.toHexString(b & 0xFF);
  }
  /**
   * @param args
   * @throws IOException 
   */
  public static void main(String[] args) throws IOException {
    InputStream stream = TestBufferedImage.class.getClassLoader().getResourceAsStream("test.png");
    BufferedImage image = ImageIO.read(stream);
    stream.close();
    log("Image loaded succesfully, width=" + image.getWidth() + " height=" + image.getHeight());
    log("Converting from 32-bit to 24-bit...");
    DataBufferByte buffer = (DataBufferByte)image.getRaster().getDataBuffer(); 
    byte[] input = buffer.getData();
    byte[] output = convertTo24Bit(input);
    log("Converted total of " + input.length + " bytes to " + output.length + " bytes");
  }
  private static byte[] convertTo24Bit(byte[] input) {
    int dataLength = input.length;
    byte[] convertedData = new byte[ dataLength * 3 / 4 ];
    for (int i = 0, j = 0; i < dataLength; i+=4, j+=3) {
      convertIntByteToByte(input, i, convertedData, j);
    }
    return convertedData;
  }
  private static void convertIntByteToByte(byte[] src, int srcIndex, byte[] out, int outIndex) {
    byte r = src[srcIndex];
    byte g = src[srcIndex+1];
    byte b = src[srcIndex+2];
    byte a = src[srcIndex+3];
    out[outIndex] = r;
    out[outIndex+1] = g; 
    out[outIndex+2] = b; 
    log("i=" + srcIndex 
        + " Converting [" + toByteString(r) + ", " + toByteString(g) 
        + ", " + toByteString(b) + ", " + toByteString(a) + "] --> ["
        + toByteString(out[outIndex]) + ", " + toByteString(out[outIndex+1])
        + ", " + toByteString(out[outIndex+2]) + "]"
        );
  }
}
Output when run from Eclipse (Version: Juno Service Release 2 Build id: 20130225-0426):
Image loaded succesfully, width=5 height=5
Converting from 32-bit to 24-bit...
i=0 Converting [aa, cc, ee, ff] --> [aa, cc, ee]   // <-- Bytes have the correct order
i=4 Converting [0, 0, 0, ff] --> [0, 0, 0]
i=8 Converting [0, 0, 0, ff] --> [0, 0, 0]
.....
i=96 Converting [0, 0, 0, ff] --> [0, 0, 0]
Converted total of 100 bytes to 75 bytes
Output when run from command line (Windows Vista) with java test.TestBufferedImage:
Image loaded succesfully, width=5 height=5
Converting from 32-bit to 24-bit...
i=0 Converting [ff, ee, cc, aa] --> [ff, ee, cc]    // <-- Bytes are returned with a different byte order!
i=4 Converting [ff, 0, 0, 0] --> [ff, 0, 0]
i=8 Converting [ff, 0, 0, 0] --> [ff, 0, 0]
.....
i=96 Converting [ff, 0, 0, 0] --> [ff, 0, 0]
Converted total of 100 bytes to 75 bytes
So has anyone encountered a similar issue and/or can explain what is actually going on? Why the byte order is different when running from inside Eclipse?
 
    