Python UnboundLocalError Embedded def

Question

This usually works; however, it's not this time:

def fn(text):
    def fn2():
        print text

    fn2()

How can I fix this?

Thanks.

Edit: I don't want to pass in text.

Maybe a solution: http://stackoverflow.com/questions/3190706/nonlocal-keyword-in-python-2-x — Waleed Khan, Aug 08 '13 at 21:15

score 0 · Answer 1 · answered Aug 08 '13 at 21:14

0

I would suggest reading this page: http://eli.thegreenplace.net/2011/05/15/understanding-unboundlocalerror-in-python/

So where does the exception come from? Quoting the FAQ:

This is because when you make an assignment to a variable in a scope, that variable becomes local to that scope and shadows any similarly named variable in the outer scope.

answered Aug 08 '13 at 21:14

Brian H

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the posted code _works_, so presumably it's not what's actually being run. – Eevee Aug 08 '13 at 21:43

Python UnboundLocalError Embedded def

1 Answers1