Why does the following code compile but not run?

Question

class Demo
{
    Demo()
    {
        System.out.println("Hello From Demo");
    }
}

class demo
{   
    demo()
    {
        System.out.println("Hello From Small Demo");
    }
}

class Test
{
    public static void main(String arg[])
    {
        Demo d1=new Demo();
        demo d2=new demo();
    }
}

This code compiles but not doesn't run; When I try to run this program, it gives a classNotFoundException. What am I doing wrong?

How are you trying to run the code? From the command line or an ide? — nullByteMe, Aug 09 '13 at 11:02
Are these classes all defined in the same file? How did you run the program? — James McLeod, Aug 09 '13 at 11:03
Go through [this](http://stackoverflow.com/questions/10890805/case-sensitivity-of-java-class-names) post it might help you. — Vinay, Aug 09 '13 at 11:09
@mluisbrown Not a strict duplicate, but explains why it can fail on some systems. Good find — kiheru, Aug 09 '13 at 11:18

Joop Eggen · Answer 1 · 2013-08-09T11:28:12.773

12

Under Unix, and/or compiled into a .jar application, file names are case case-sensitive. And all would work: demo.class, Demo.class.

Under Windows the compilation of demo and Demo will overwrite one file.

edited Aug 09 '13 at 11:28

answered Aug 09 '13 at 11:18

Joop Eggen

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Why does the following code compile but not run?

1 Answers1