How to retrieve Name from Email Address

Question

With javascript, how do we remove the @gmail.com or @aol.com from a string so that what only remains is the name?

var string = "johndoe@yahoo.com";

Will be just "johdoe"? I tried with split but it did not end well. thanks.

Answer 1

var email = "john.doe@example.com";
var name   = email.substring(0, email.lastIndexOf("@"));
var domain = email.substring(email.lastIndexOf("@") +1);

console.log( name );   // john.doe
console.log( domain ); // example.com

The above will also work for valid names containing @ (tools.ietf.org/html/rfc3696^{Page 5}):

john@doe
"john@@".doe
"j@hn".d@e

• String.prototype.substring()
• String.prototype.lastIndexOf()

Using RegExp:

Given the email value is already validated, String.prototype.match() can be than used to retrieve the desired name, domain:

String match:

const name   = email.match(/^.+(?=@)/)[0];    
const domain = email.match(/(?<=.+@)[^@]+$/)[0]; 

Capturing Group:

const name   = email.match(/(.+)@/)[1];    
const domain = email.match(/.+@(.+)/)[1];

To get both fragments in an Array, use String.prototype.split() to split the string at the last @ character:

const [name, domain] = email.split(/(?<=^.+)@(?=[^@]+$)/);
console.log(name, domain);

or simply with /@(?=[^@]*$)/.
Here's an example that uses a reusable function getEmailFragments( String )

const getEmailFragments = (email) => email.split(/@(?=[^@]*$)/);

[ // LIST OF VALID EMAILS:
  `info@example.com`,
  `john@doe@example.com`,
  `"john@@".doe@example.com`,
  `"j@hn".d@e@example.com`,
]
.forEach(email => {
  const [name, domain] = getEmailFragments(email);
  console.log("DOMAIN: %s NAME: %s ", domain, name);
});

Answer 2

You should take note that a valid email address is an incredibly sophisticated object and may contain multiple @ signs (ref. http://cr.yp.to/im/address.html).

"The domain part of an address is everything after the final @."

Thus, you should do something equivalent to:

var email = "johndoe@yahoo.com";
var name = email.substring(0, email.lastIndexOf("@"));

or even shorter,

var name = email.replace(/@[^@]+$/, '');

If you want both the name and the domain/hostname, then this will work:

var email = "johndoe@yahoo.com";
var lasta = email.lastIndexOf('@');
var name, host;
if (lasta != -1) {
    name = email.substring(0, lasta);
    host = email.substring(lasta+1);
    /* automatically extends to end of string when 2nd arg omitted */
} else {
    /* respond to invalid email in some way */
}

Answer 3

And another alternative using split:

var email = "john.doe@email.com";
var sp = email.split('@');

console.log(sp[0]); // john.doe
console.log(sp[1]); // email.com

Answer 4

Try it using substring() and indexOf()

var name = email.substring(0, email.indexOf("@"));

Answer 5

var email = "johndoe@yahoo.com";
email=email.replace(/@.*/,""); //returns string (the characters before @)

Answer 6

You can try with the replace() and regular expression. You can read more about replace() using regex here

var myEmail = 'johndoe@yahoo.com';
var name= myEmail.replace(/@.*/, "");
console.log(name);

This returns the string before @

Answer 7

As shown in How to remove or get domain name from an e-mail address in Javascript?, you can do it using the following code:

const getDomainFromEmail = email => {
  let emailDomain = null;
  const pos = email.search('@'); // get position of domain
  if (pos > 0) {
    emailDomain = email.slice(pos+1); // use the slice method to get domain name, "+1" mean domain does not include "@"
  }
  return emailDomain;
 };

const yourEmail = "jonth.nt49@4codev.com"
 console.log(getDomainFromEmail(yourEmail));
 // result : 4codev.com

Answer 8

This simple regex will do the needful.
/^.*(?=@)/g.

Example:

"johndoe@yahoo.com".match(/^.*(?=@)/g); // returns Array [ "johndoe" ]