replace deprecated ereg with what_function()

Question

I have a code which read file inside a directory. But I am using ereg(), Now I am getting a deprecated error on PHP 5.3.

After search on google, someone said to replace ereg() with perg_match().

But after replacing with perg_math() I am getting an error:

preg_match(): No ending delimiter '.' found

I am not a PHP expert kndly fix this problem.

$path = THEME_DIR.'/'.$path;
foreach(array_diff(scandir($path), array('.', '..')) as $f) 
    if (is_file($path . '/' . $f) && (('.php') ? ereg('.php' . '$' , $f) : 1)) 
        $l[] = $f;
return $l;

You need to add delimiters to your regex when using `preg_match`. http://php.net/manual/en/regexp.reference.delimiters.php — elclanrs, Sep 16 '13 at 05:16
Try to read this: [Switching from PHP !ereg and !eregi to preg_match](http://stackoverflow.com/questions/6465601/switching-from-php-ereg-and-eregi-to-preg-match) or this [How can I convert ereg expressions to preg in PHP?](http://stackoverflow.com/questions/6270004/how-can-i-convert-ereg-expressions-to-preg-in-php) — teo, Sep 16 '13 at 05:26

score 2 · Accepted Answer · edited May 23 '17 at 12:05

preg_match regex should be inside the delimeters.. "/your regex here/".. the deprecated POSIX regex were the one which did not require any delimeter.. eg ereg(")

so just change your regex to

"/old regex/"

PHP regular expressions: No ending delimiter '^' found in for reference

$path = THEME_DIR.'/'.$path;
foreach(array_diff(scandir($path), array('.', '..')) as $f) 
    if (is_file($path . '/' . $f) && (('.php') ? ereg('/.php' . '$/' , $f) : 1)) 
        $l[] = $f;
return $l;

replace deprecated ereg with what_function()

1 Answers1