Counting in Lojban, an artificial language developed over the last forty years, is easier than in most languages The numbers from zero to nine are:
0  no
1  pa
2  re
3  ci
4  vo
5  mk
6  xa
7  ze
8  bi
9  so
Larger numbers are created by gluing the digit together. For example, 123 is "pareci". Write a program that reads in a lojban string (representing a no. less than or equal to 1,000,000) and output it in numbers.
I don't know what happened; it seems that my programme is not checking the if statement       if (str.substring(i-2,i) == q[ale]).  The rest of the loop is working fine.  Any advice?
public class apple {
    public static void main(String[] args) {
        String [] q =
           new String[10];//"no","pa","re","ci","vo","mk","xa","ze","bi","so"];
        q[0] = "no";
        q[1] = "pa";
        q[2] = "re";
        q[3] = "so";
        q[4] = "ci";
        q[5] = "vo";
        q[6] = "mk";
        q[7] = "xa";
        q[8] = "ze";
        q[9] = "bi";
        //q[0] = "so";
        int ln;
        String str = "nocipa";
        ln = str.length();
        if (ln % 2 != 0)
        {
            System.out.println("Invalid number");
        }
        else
        { 
            for (int i = 2; i <=ln-2; i = i + 2)
            {
                for (int ale = 0; ale < 9; ale++)
                {
                    if (str.substring(i-2,i) == q[ale])
                    {
                        System.out.print("hello" ); 
                    }
                }
            }
        }
    }
}
 
     
     
    