Python basic string array

Question

Can anybody explain me this: s[81:67:-1]

When s is "this is me asking a question on stackoverflow.com and hoping to get an answer that will help me further"

docs can — http://docs.python.org/2.3/whatsnew/section-slices.html — alexvassel, Oct 09 '13 at 13:27
Sorry for dup, I just did not know how to call this method. Now I know: "slice notation" — grmbl, Oct 09 '13 at 13:36

thefourtheye · Accepted Answer · 2013-10-09T13:32:58.647

2

It is accessing string in reverse. From 81st character, till 67th character. The step value is -1. If you specify a positive value, you ll get nothing.

print s[81:67:-1]
print s[81:67:1]

Output

taht rewsna na

You can read more about it here. It is called slicing notation.

edited Oct 09 '13 at 13:32

answered Oct 09 '13 at 13:26

thefourtheye

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Will it return the string in reverse? Or is it the same as `s[67:81]` – grmbl Oct 09 '13 at 13:28
thx @thefourtheye, will accept your answer when I can ^^ must say that python is beautiful, maybe I'll try & learn it. – grmbl Oct 09 '13 at 13:31
@grmbl It will return the string in reverse, as you guessed. – thefourtheye Oct 09 '13 at 13:33
@grmbl Indeed, it is. Glad I could help. :) – thefourtheye Oct 09 '13 at 13:33

score 1 · Answer 2 · answered Oct 09 '13 at 13:28

1

You are accessing the element from position 81 to 67 but in reverse order (:-1 achieve this)

So, you are iterating over elements from position 67 to 81.

answered Oct 09 '13 at 13:28

user278064

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Python basic string array

2 Answers2