I would like to know how to slice my Python string every nth character/letter (in my case the 5th character/letter).
So I have this string "ilikestackoverflow" and I would like for the output to be "ilike stack overf low".
Asked
Active
Viewed 666 times
2
Stefan van den Akker
- 6,661
- 7
- 48
- 63
iabestever
- 25
- 1
- 6
2 Answers
4
x = zip(*[iter(my_array)]*5)
is a cool but hard to read way of doing it
typically it is done with a list comprehension though
n = 5
x = [my_array[i:i+n] for i in range(0,len(my_array),n)]
this post explains the iter answer best http://www.stavros.io/posts/brilliant-or-insane-code/
Joran Beasley
- 110,522
- 12
- 160
- 179
-
could you please explain how this works? – iabestever Oct 10 '13 at 18:34
-
3chicken blood and pentagrams – Joran Beasley Oct 10 '13 at 18:36
-
where did i come from? – iabestever Oct 10 '13 at 18:45
-
`for i in BLAH` creates a locally scoped i ... its standard list comprehension stuff – Joran Beasley Oct 10 '13 at 18:50
1
What about a good-ol' regular expression?
>>> string = "Ireallylovemyregularexpressions!"
>>> print re.sub(r'(.{5})', r'\1 ', string)
Ireal lylov emyre gular expre ssion s!
(.{5}) matches every 5 characters, r'\1 ' replaces these 5 characters by the same 5 characters plus a white-space character.
This also works:
>>> m = re.split(r'(.{5})', 'Ilovestackoverflowsobad')
>>> print m
['', 'Ilove', '', 'stack', '', 'overf', '', 'lowso', 'bad']
>>> for word in m:
... if word == '':
... pass
... else:
... print word,
...
Ilove stack overf lowso bad
Stefan van den Akker
- 6,661
- 7
- 48
- 63
-
1+1 although this reminds me about that saying "I had a problem, and I thought 'I know Ill use regular expressions' ..." – Joran Beasley Oct 10 '13 at 19:13
-
1Haha, yeah, I agree, but I was studying regular expressions, and you know: if you have a hammer, every problem starts looking like a nail. – Stefan van den Akker Oct 10 '13 at 19:16