How to remove beginning of a string

Question

So at school, we are meant to be making a binary and decimal converter. So far I have discovered the bin() function and it gives me roughly what I need:

bin(10)
#0b1010

However, I was wandering how I would go about removing the 0b at the beginning so that I am left with simply 1010.

Does anyone actually know what the 0b means?

the 0b means its binary, just like 0x means its hex. – Hoopdady Oct 21 '13 at 15:04 — Hoopdady, Oct 21 '13 at 15:04

score 4 · Answer 1 · edited May 23 '17 at 12:28

4

The 0b means it is binary. And, to remove it, simply do this:

>>> bin(10)
'0b1010'
>>> bin(10)[2:]
'1010'
>>> bin(12345)
'0b11000000111001'
>>> bin(12345)[2:]
'11000000111001'
>>>

This solution takes advantage of Python's slice notation.

edited May 23 '17 at 12:28

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answered Oct 21 '13 at 15:04

score 2 · Answer 2 · answered Oct 21 '13 at 15:05

2

I am not sure exactly what you are asking, but I think its "How do i trim the start of a string off"

And you can do that with slicing:

>>> s = "I am a string"
>>> s[5:]
'a string'

So in your case it would be:

>>> bin(10)[2:]
'1010'

answered Oct 21 '13 at 15:05

Inbar Rose

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score 1 · Answer 3 · edited May 23 '17 at 12:05

1

There is another way to convert a number to binary without the 0b at the beginning

>>> '{0:0b}'.format(10)
'1010'

This question will be helpful to you Converting integer to binary in python

edited May 23 '17 at 12:05

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answered Oct 21 '13 at 19:12

kyle k

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How to remove beginning of a string

3 Answers3