How do I put a method as a parameter in a method call?

Question

I'm trying to write a method in java that passes in another method as a parameter.

This is the method call in main:

    Functions.print("total",Functions.compute(scoreArray),Functions.find(scoreArray));

So far i have this as the method signature:

    public void print(String str, ...)

I have the compute and find methods already written. I don't know how to input them as parameters.

What do you think `javascript` and `java` are? – Sotirios Delimanolis Oct 27 '13 at 21:22 — Sotirios Delimanolis, Oct 27 '13 at 21:22
Perhaps you could use an interface. – Josh M Oct 27 '13 at 21:24 — Josh M, Oct 27 '13 at 21:24

score 0 · Answer 1 · answered Oct 27 '13 at 21:22

0

You can't currently do it with Java (well, you can but it's really roundabout)

There's a guava library that makes it easier to do functional programming with collections: https://code.google.com/p/guava-libraries/wiki/FunctionalExplained

answered Oct 27 '13 at 21:22

tom

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score 0 · Answer 2 · answered Oct 27 '13 at 21:25

Yes, but not directly. Create an interface:

public interface MyFuncFromAToB{
    public SomeClass calculate(SomeOtherClass in);
}

and accept that.

_{On Java 8 you'll be able to use Lambdas. When that comes around keep accepting the same interface(it must have only one method) and you'll receive lambdas and method pointers with that signature.}

score 0 · Answer 3 · answered Oct 27 '13 at 21:35

0

Java and javascript are two very different languages. Java (currently) doesn't have any functional programming features; methods (functions) are not Objects and so cannot be passed around like objects.

answered Oct 27 '13 at 21:35

trf

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How do I put a method as a parameter in a method call?

3 Answers3