Split string based on second occurrence of delimiter using javascript

Question

I have a dynamically formed string like - part1.abc.part2.abc.part3.abc whose length is unknown

In this string I want to get the substring based on second occurrence of "." so that I can get and part1.abc part2.abc part3.abc.

And if the string is like - part1.abc.part2.abc.part3.abc.part4 output must be like part1.abc part2.abc part3.abc part4

How to get this?

http://stackoverflow.com/questions/5494691/cutting-a-string-at-nth-occurrence-of-a-character — Gopesh Sharma, Nov 05 '13 at 05:44
Even a simple split and then processing it in groups will do. — user568109, Nov 05 '13 at 05:45

score 3 · Accepted Answer · answered Nov 05 '13 at 05:56

3

Something like this :

str="part1.abc.part2.abc.part3.abc.part4"
temp=str.split('.');
out=[]
for(i=0; i<temp.length;i=i+2)
out.push(temp.slice(i,i+2).join('.'));
//["part1.abc", "part2.abc", "part3.abc", "part4"]

answered Nov 05 '13 at 05:56

user568109

47,225
17
99
123

score 3 · Answer 2 · answered Nov 05 '13 at 10:52

3

As suggested in my comment, the simplest (and fastest) way is to use a regular expression and match:

// ['part1.abc', 'part2.abc', 'part3.abc', 'part4']
'part1.abc.part2.abc.part3.abc.part4'.match(/[^.]+(\.[^.]+)?/g);

answered Nov 05 '13 at 10:52

RobG

142,382
31
172
209

score 1 · Answer 3 · answered Nov 05 '13 at 06:05

Simple function which allows you to specify the number of items to join together and delimiter which you can use to join them.

var concatBy = function(list, delimiter, by) {
    var result = [];
    for (var i = 0; i < list.length; i += by) {
        result.push(list.slice(i, i + by).join(delimiter))
    }
    return result;
}

concatBy('part1.abc.part2.abc.part3.abc'.split('.'), '.', 2) // returns concatBy('part1.abc.part2.abc.part3.abc.part4'.split('.'), '.', 2)
concatBy('part1.abc.part2.abc.part3.abc.part4'.split('.'), '.', 2) // returns ["part1.abc", "part2.abc", "part3.abc", "part4"]

Split string based on second occurrence of delimiter using javascript

3 Answers3

Linked

Related