How can i store a int value=100,000 into a ArrayList<Byte>. I can't type cast because the value would change .
Is there any mechanism by which i can allocate 4 bytes in Arraylist and store the integer.
Or is it possible to with a byte[] array?
Or is it possible to with a byte[] array?
Yes, BigInteger have a method toByteArray()
byte[] resultBArray= yourBigInteger.toByteArray();
Even then you cannot store in ArrayList<Byte>, Since Byte[] is not Byte
But that seems not quite good for me, You can take a individual List with Byte[] or direct List<BigInteger>
BigInteger yourBigInteger = new BigInteger(String.valueOf(100000));
byte[] resultBArray= yourBigInteger.toByteArray();
to get it back
 int i=    new BigInteger(bytes).intValue();
 
    
    Try:
BigInteger value=new BigInteger("100000");
List<byte[]> list=new   ArrayList<>();
list.add(value.toByteArray());//Put BigInteger as byte[]
BigInteger returnValue= new BigInteger(list.get(0));// Return value from list
System.out.println(returnValue);
 
    
    Just do
 byte[] byteArray = new BigInteger("100000").toByteArray();
 List<Byte> bytes = new ArrayList<>();
    for(byte b : byteArray)
        bytes.add(b);
