How to use name of parameter inside a declared path for a file - java

Question

I have a method called createCSV where I convert a List into a csv file. I want to use a pathname for the new file with the name of the List, which I give as a param. How can i do this? Here is my code:

public static File createCSV(List<String[]> custList) {

    String methodName = "createCSV";
    String csv = "/home/oracle/outputcsv/" + custList + ".csv"; // pathname
                                                                // with
                                                                // listname.csv
    File file = new File(csv);

    try {
        custList = new ArrayList<String[]>();

        FileWriter filewr = new FileWriter(file);
        CSVWriter writer = new CSVWriter(filewr);

        custList.add(0, new String[] { "customerId" });

        for (String[] list : custList) {

            custList.add(0, new String[] { "customerId" });

        }

        writer.writeAll(custList);
        logger.debug("[{}] custlist = {}", methodName, custList);

        logger.debug("[{}]CSV written successfully", methodName);
        writer.close();

        logger.debug("[{}]The file is supposed to be :) : {} ", methodName,
                file);
        // return file;

    } catch (IOException e) {
        e.printStackTrace();
        logger.debug("[{}] IOException {}", methodName, e);
    }

    return file;

}

I also have a problem in displaying all my list elements. I tried to use a for statement but it didn't help.

Thanks a lot!

Do you mean that you do something like List foo = null; createCSV(foo); and then you want to write it as foo.csv? — Rhand, Nov 20 '13 at 15:42

score 2 · Accepted Answer · answered Nov 20 '13 at 15:47

2

What you’re asking for is not possible in Java. The parameter names are not retained; because what name would you give an argument of 1, or new Object()?

However, simply add a second parameter to your method:

public static File createCSV(List<String[]> custList, String filename) {
    …
}

answered Nov 20 '13 at 15:47

Bombe

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That was it, thank you very much! Furthermore, can you tell me what am I doing wrong in the parsing of the List? Because only one parameter is written, yet i have more in the List. – Razvan N Nov 20 '13 at 15:57

score 2 · Answer 2 · answered Nov 20 '13 at 15:48

custlist is your list and you want a String to concatenate to your csv path. Add the list name as a parameter to your method.

createCSV(List<String[]> custList, String yourListName)

then

String csv = "/home/oracle/outputcsv/" + yourListName + ".csv";

score 0 · Answer 3 · edited May 23 '17 at 12:28

0

In addition to the solution presented by Veronica and Bombe. If you are unwilling to type in the parameter name, you could try to recover it using techniques discussed here: Java Reflection: How to get the name of a variable?

edited May 23 '17 at 12:28

Community

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1

answered Nov 20 '13 at 15:55

Rhand

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How to use name of parameter inside a declared path for a file - java

3 Answers3