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I am new in R and I was wondering if I can heatmap my table or matrix which contain TRUE and FALSE ie : Condition1 Conditions2 . . . Id1 TRUE FALSE Id2 FALSE TRUE . . . My excuse for this naive question and any proposition is welcome to make a heatmap or any tool to visualize my table or matrix by color code and apply clustering or dendrogram based on it.
Thank you in advance

user3037937
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  • I found a similar question [HERE](http://stackoverflow.com/questions/3280705/how-to-convert-2d-binary-matrix-to-black-white-plot) – Stu Nov 26 '13 at 19:48

2 Answers2

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Assuming you can easily convert TRUE/FALSE to 1,0 numeric

x<-data.frame(y=sample(c(1, 0),10, replace=TRUE), z=sample(c(1, 0),10, replace=TRUE))
heatmap(as.matrix(x))

if needed, to change TRUE/FALSE to 1/0 , 

x[x==TRUE]<-1
x[x==FALSE]<-0
Ananta
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  • Actually, you don't need to turn T to 1 or F to 0. It will do that automatically. – Stu Nov 26 '13 at 19:39
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    Hmm, I get following error `Error in heatmap(as.matrix(x)) : 'x' must be a numeric matrix` without converting, may be for `image` its ok, but not for `heatmap` – Ananta Nov 26 '13 at 19:42
  • it will do 1's and 0's with `as.numeric(x)` – Señor O Nov 26 '13 at 20:58
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Use the image() function:

> x=matrix(c(T,F,T,F,F,F,T,T,F,T,T,T,F,F,F,T),ncol=4)
> x
      [,1]  [,2]  [,3]  [,4]
[1,]  TRUE FALSE FALSE FALSE
[2,] FALSE FALSE  TRUE FALSE
[3,]  TRUE  TRUE  TRUE FALSE
[4,] FALSE  TRUE  TRUE  TRUE
> image(t(x),axes=F)
> axis(2,at=seq(0,1,(1/(nrow(x)-1))),labels=nrow(x):1)
> axis(3,at=seq(0,1,(1/(ncol(x)-1))),labels=1:ncol(x))

Give it a shot!

Stu
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