Convert the following code to a oneliner

Asked Nov 29 '13 at 19:57

Active Nov 29 '13 at 19:57

Viewed 62 times

I need to turn this code to one line code, without using yield, but it could involve the use of lambda.

f is a function an x0 is the first given number to enter the function

def give_value(f,x0):
    yield x0
    fx = x0
    while True:
        yield f(fx)
        fx = f(fx)

any ideas?

asked Nov 29 '13 at 19:57

matanb

This will _always_ yield `x0`. The rest of your code won't even be touched. Are you sure this is your function? I mean try the following code, it will go into an infinite [loop](https://dpaste.de/O2H6) – Games Brainiac Nov 29 '13 at 19:59
5

@GamesBrainiac: Are you sure you know what `yield` does? – user2357112 Nov 29 '13 at 20:02
Hi, thanks for the reply, the code runs and gets to the inner yield inside the "while" block – matanb Nov 29 '13 at 20:02
@user2357112 Why yes. – Games Brainiac Nov 29 '13 at 20:03
@GamesBrainiac It is an infinite generator. Why do you claim it only yields `x0`? – Janne Karila Nov 29 '13 at 20:09
1

@MatanB Why do you need to turn it into one line? – Janne Karila Nov 29 '13 at 20:12

0 Answers0