php glob and scandir function is not working on web server

Question

i am using this glob function on my website dont know what is the problem.wasted too much time on this.its working on localhost but not working in webserver. please help me

code :

 $result = mysql_query($qry) or die ("Query failed");
    $count=mysql_num_rows($result);
    $HTML='';
    if($count > 0){
    while ($friendList = mysql_fetch_array($result))
     {

     $_SESSION['PropertyId'] = $friendList['property_Id'];
     $Username = $friendList['UserName'];
     $qry1 = "SELECT Mobile_Number1,FirstName FROM registration WHERE UserName = '".$Username."'";
    $result1 = mysql_query($qry1) or die ("Query failed");
    $friendList1 = mysql_fetch_array($result1);
    $mobNo = $friendList1['Mobile_Number1'];
    $Name = $friendList1['FirstName']; 
    $image = "";
    $dir = "propertyImages/".$friendList['property_Id']."";
    $files = array();
    $files = glob("$dir/*.*");
    $image = "";
    print_r($files);
    if (count($files) > 0) 
    {
    $image = $files[0];
    }
    else
    {
    $image = 'img/1.jpg';
    }

i want only first image from that directory.but in array it does not displaying anything on server — dvirus, Jan 06 '14 at 07:26
are you sure `$friendList['property_Id']` is set, also put this at the begin of your script to see the error if has any `error_reporting(-1); ini_set('display_errors', true);` — Emilio Gort, Jan 06 '14 at 07:27
$friendList['property_Id'] is coming from database.and it returning proper value — dvirus, Jan 06 '14 at 07:29
@NabilKadimi its working on localhost but not working in web server — dvirus, Jan 06 '14 at 07:31
your folder isn't empty and the script doesnt show any error with the error_reporting? what system have your server? — Emilio Gort, Jan 06 '14 at 07:33
yes i am using ajax that data is coming dyanamically without refresh the page..but i checked without ajax also — dvirus, Jan 06 '14 at 07:37
the error reporting doesnt show nothing??if you dont have set an error reporting you cant see any error — Emilio Gort, Jan 06 '14 at 07:38
you have two options in php.ini or write this `error_reporting(-1); ini_set('display_errors', true);` at top of your script — Emilio Gort, Jan 06 '14 at 07:39
@EmilioGort and where i can see those error i have added this on my php page — dvirus, Jan 06 '14 at 07:43
I dont know my friend what could be the issue, the php's manual say: `Note: On some systems it is impossible to distinguish between empty match and an error.` try http://us1.php.net/readdir instead to get the work done, and read [Why shouldn't I use mysql_* functions in PHP?](http://stackoverflow.com/questions/12859942/why-shouldnt-i-use-mysql-functions-in-php) — Emilio Gort, Jan 06 '14 at 07:56

score 0 · Answer 1 · answered Jan 10 '14 at 12:26

As @Emilio stated, try readdir() instead of glob(), especially because you are not really needing the pattern recognition glob() does provide.

Could you give this a try?

// enable error reporting
error_reporting(E_ALL);
ini_set('display_errors', '1');

// initialise empty $files array
$files= array();

if (file_exists($dir)) {
  $dh= opendir($dir);
  if ($dh) {
    while ($file= readdir($dh)) {

      // skip "." and ".."
      if ($file != "." && $file != "..") {
        echo "$file\n";
        $files[]= $file;
      }
    }
    closedir($dh);
  } else {
    print 'Directory handle could not be opened.';
  }
} else {
  print 'Directory not accessible or does not exist.';
}

General comments:

1.) another +1 for @Emilio's comment about mysql_* functions

2.) If you are running your script on a shared host you may also experience problems due to safe_mode being enabled.

3.) Checking for errors when using ajax calls: Firebug's Network panel will reveal the response returned from the server, just have it open while doing the call. If any error is output by the server you will see the error on the Response tab of the corresponding AJAX call.

4.) Regarding code: you don't need to initialise variables like $image or $files if they are directly overwritten, the two double quotes at the end of the $dir = ... are also obsolete. I would also recommend to decide for one variable style, best would be CamelCase syntax with a lowercase letter after the $.

i tried this code it prints "Directory not accessible or does not exist" but i have files in that folder — dvirus, Jan 11 '14 at 05:02
Files that you see using FTP which does not necessarily mean the owner of the PHP process does see. Tell us a bit about your production server, are you hosting it or is it on a shared host? If you are logged in via FTP, try to set the directory permissions on that folder to 0755 to make it readable by everyone. — SaschaM78, Jan 11 '14 at 09:58
Another idea to check path issues: if the directory containing the images is accessible for web users, upload a file containing `` to the directory and browse to that file, check the location returned in `SERVER['SCRIPT_FILENAME']` if it matches the directory you try to open in your script. If they are identical it has to be access permissions. — SaschaM78, Jan 11 '14 at 10:03

php glob and scandir function is not working on web server

1 Answers1