PHP Notice Undefined index. Searching alternative way

Question

I've tried alternative ways from similar questions but didn't get any good result. I've also tried var_dump($_POST) and isset() methods too. My code is:

<?php
function inputFILTER($data){
    $data = trim($data);
    $data = stripslashes($data);
    $data = strip_tags($data);
    $data = htmlspecialchars($data);
    return $data;
    }
    $question="";
if ($_SERVER["REQUEST_METHOD"] == "POST"){
    $str=$_POST['supportinput'];
    $question=inputFILTER($str);
    echo $question;
}
?>

Hello @JohnConde I've tried all them but didnt get any happy result. Line: Notice: Undefined index: supportinput in ...\live.php on line 12 — RufatN, Jan 09 '14 at 17:05
Can you show your html or form section here ! may be input name not the same — Krish R, Jan 09 '14 at 17:07
" name="support_form" id="support_form"> The form is sent by Ajax Send method. — RufatN, Jan 09 '14 at 17:09
where is your submit button and its action ? post your `showResult()` code. — Krish R, Jan 09 '14 at 17:10
Hello @KrishR. It sends with Ajax code when on key down or up. It doesn't need submit button. — RufatN, Jan 09 '14 at 17:14
function showResult(){ var xmlhttp; var formData=$("#support_form").serialize(); if (window.XMLHttpRequest) { xmlhttp=new XMLHttpRequest(); }else { xmlhttp=new ActiveXObject("Microsoft.XMLHTTP"); } xmlhttp.onreadystatechange=function() { if (xmlhttp.readyState==4 && xmlhttp.status==200) { document.getElementById("result").innerHTML=xmlhttp.responseText; } } xmlhttp.open("POST","/respondeo/live.php",true); xmlhttp.setRequestHeader("Content-type","application/x-www-form-urlencoded"); xmlhttp.send("formData"); } — RufatN, Jan 09 '14 at 17:17
change this `xmlhttp.send("formData");` into `xmlhttp.send(formData);` — Krish R, Jan 09 '14 at 17:20

score 0 · Accepted Answer · answered Jan 09 '14 at 17:24

Use this,

xmlhttp.send(formData);

instead of

xmlhttp.send("formData");

Javascript:

function showResult(){ 
    var xmlhttp; 
    var formData=$("#support_form").serialize(); 
    if (window.XMLHttpRequest) { 
           xmlhttp=new XMLHttpRequest(); 
     }else { 
             xmlhttp=new ActiveXObject("Microsoft.XMLHTTP"); 
       } 
       xmlhttp.onreadystatechange=function() { 
             if (xmlhttp.readyState==4 && xmlhttp.status==200) {                                                      document.getElementById("result").innerHTML=xmlhttp.responseText; 
              } 
        }
       xmlhttp.open("POST","/respondeo/live.php",true);
       xmlhttp.setRequestHeader("Content-type","application/x-www-form-urlencoded");
       xmlhttp.send(formData); 
}

PHP Notice Undefined index. Searching alternative way

1 Answers1