Beginners blackjack game using loops

Question

I'm trying to create a blackjack program for school and I don't understand why my program keeps starting over after i ask for another card once I get my first two cards. Any help would be great. My code for everything is below.

import java.util.Scanner;
import java.util.*;

public class BlackjackGame {

    public static void main(String[] args) {

        String anotherCard, playAgain = "y", ctn;
        int nextCard, card1, card2, dCard1, dCard2;
        int cardTotal = 0, dTotal = 0;

        Scanner keyboard = new Scanner(System.in);

        Random random = new Random();

        // Begin dealing the players first two cards

        while (playAgain == "y")
        {
            //dealers first two random cards
            dCard1 = random.nextInt(10) + 1;
            dCard2 = random.nextInt(10) +1;

            //players first two random cards and card total
            card1 = random.nextInt(10) + 1;
            card2 = random.nextInt(10) + 1;
            cardTotal = card1 + card2;

            //Dealers two card total and display only one dealer card
            dTotal = dCard1 + dCard2;
            System.out.println("Dealer shows: " + dCard1);

            //Display players first two cards & card total
            System.out.println("First Cards: " + card1 + ", " +card2);
            System.out.println("Total: "+ cardTotal);

            System.out.print("Another Card (y/n)?: ");
            anotherCard = keyboard.nextLine();

            while (anotherCard == "y")
            {
                nextCard = random.nextInt(10) + 1;
                cardTotal += nextCard;
                System.out.println("Card: " + nextCard);
                System.out.println("Total: " + cardTotal);

                if (cardTotal > 21)
                {
                System.out.println("You busted, Dealer Wins");
                System.out.println("Do you want to play again? (y/n): ");
                playAgain = keyboard.nextLine();
                }   
                if (cardTotal < 21)

                System.out.print("Another Card (y/n)?: ");
                anotherCard = keyboard.nextLine();
                if (anotherCard == "n")
                System.out.print("Press c to continue dealers cards");
                ctn = keyboard.nextLine();


                while (ctn == "c" && dTotal < 17)
                {
                    nextCard = random.nextInt(10) + 1;
                    dTotal += nextCard;

                    if (dTotal > 21)
                    {
                    System.out.println("Dealer Busts, You Win!");
                    System.out.println("Play Again? (y/n): ");
                    playAgain = keyboard.nextLine();
                    if (playAgain.equalsIgnoreCase("y"))
                            playAgain = "y";
                        else
                            System.exit(0);
                    }

                }

            }

        }
    }
}

Read [How do I compare strings in Java?](http://stackoverflow.com/questions/513832/how-do-i-compare-strings-in-java) — PakkuDon, Jan 28 '14 at 00:38
Use `String`'s `equals` method to compare string values, not the `==` operator. — rgettman, Jan 28 '14 at 00:38

score 3 · Answer 1 · answered Jan 28 '14 at 00:50

This expression:

if (playAgain == "y")

will never be true, because the == operator is only true if both operands are the same object. To compare the value of Strings,use equals():

if (playAgain.equals("y"))

Don't feel bad. The problem is with the language - it was a stupid choice to use the == operator like that. A large proportion of questions here that this issue at their root.

Beginners blackjack game using loops

1 Answers1