This question should be really easy to answer, however I didn't find anything/don't know how to search.
def testcall(function, argument):
function(*argument)
testcall(print, "test")
# output:
t e s t
why t e s t and not test?
Asked
Active
Viewed 40 times
0
speendo
- 13,045
- 22
- 71
- 107
-
2`*argument` is breaking the string into an array of 4 chars, so you're calling `print 't', 'e', 's', 't'`; you should declare `argument` as `*argument` – vanza Feb 06 '14 at 21:11
2 Answers
4
You are using the splat syntax (*argument) to break up argument into individual characters. Then, you are passing these characters to print. It is no different than doing:
>>> print('t', 'e', 's', 't')
t e s t
>>>
Remove the * to fix the problem:
>>> def testcall(function, argument):
... function(argument)
...
>>> testcall(print, "test")
test
>>>
Community
- 1
- 1
-
ok, but how would I use this function to call a function with 2 arguments then? – speendo Feb 06 '14 at 21:15
-
-
4
Your splats are asymmetric. It should be:
def testcall(function, *argument):
function(*argument)
In general, if you want your function to behave like another function, it should accept a splat and send a splat. This answer explains the general case
